Github 同步地址: https://github.com/grandyang/leetcode/issues/83 类似题目: Remove Duplicates from Sorted List II Remove Duplicates From an Unsorted Linked List 参考资料: https://leetcode.com/problems/remove-duplicates-from-sorted-list/ https://leetcode.com/problems/remove-duplicates-from-sorted-l...
Given a sorted linked list, delete all duplicates such that each element appear onlyonce. For example, Given1->1->2, return1->2. Given1->1->2->3->3, return1->2->3. 思路:遍历链表,通过两个指针保存当前位置和当前位置的前一个位置。假设两指针所指节点的值相等。则删除当前节点。假设不等。
本题类似于 LeetCode 82. Remove Duplicates from Sorted List II, 解题思路同 LeetCode: 82. Remove Duplicates from Sorted List II。只需要将删除当前节点的代码注释掉即可。 AC 代码 AI检测代码解析 /** * Definition for singly-linked list. * struct ListNode { * int v...
leetcode 83. Remove Duplicates from Sorted List Given a sorted linked list, delete all duplicates such that each element appear onlyonce. For example, Given1->1->2, return1->2. Given1->1->2->3->3, return1->2->3. # Definition for singly-linked list. # class ListNode(object): #...
83. 删除排序链表中的重复元素 - 给定一个已排序的链表的头 head , 删除所有重复的元素,使每个元素只出现一次 。返回 已排序的链表 。 示例 1: [https://assets.leetcode.com/uploads/2021/01/04/list1.jpg] 输入:head = [1,1,2] 输出:[1,2] 示例 2: [https
事实上很简单的,按照数据结构书上那种就行了: https://leetcode.com/problems/remove-duplicates-from-sorted-list/solution/
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2019-12-22 08:20 −原题链接在这里:https://leetcode.com/problems/remove-outermost-parentheses/ 题目: A valid parentheses string is either empty (""), "(" + A + ")", or&n... Dylan_Java_NYC 0 432 LeetCode 82. Remove Duplicates from Sorted List II ...
Leetcode 82 Remove Duplicates from Sorted List II distinctlistnodesnumbersreturn Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example, Given 1->2->3->3->4->4->5, return 1->2->5. Given 1->1->1-...
[LeetCode] Remove Duplicates from Sorted List II 移除有序链表中的重复项之二 Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example, Given 1->2->3->3->4->4->5,... 文章...