Remove All Adjacent Duplicates In String 参考资料: https://leetcode.com/problems/get-equal-substrings-within-budget/ https://leetcode.com/problems/remove-all-adjacent-duplicates-in-string-ii/discuss/392933/JavaC%2B%2BPython-Two-Pointers-and-Stack-Solution LeetCode All in One 题目讲解汇总(持续更...
Can you solve this real interview question? Remove All Adjacent Duplicates in String II - You are given a string s and an integer k, a k duplicate removal consists of choosing k adjacent and equal letters from s and removing them, causing the left and th
原题链接在这里:https://leetcode.com/problems/remove-all-adjacent-duplicates-in-string-ii/ 题目: Given a strings, akduplicate removalconsists of choosingkadjacent and equal letters fromsand removing them causing the left and the right side of the deleted substring to concatenate together. We repea...
string removeDuplicates(string s, int k) { int i, streak; // streak will store count of consecutive duplicates while(1){ i = streak = 1; bool removed = false; streak = (s[i] == s[i - 1] ? streak + 1 : 1); if(streak == k) s.erase(i - k + 1, k), streak = 1, ...
209. Remove All Adjacent Duplicates in String II刷题笔记,用栈来实现classSolution:defremovestack=collections.deque()dupliflen(stack)>0andletter==stack[-1]:duplicat
1047. Remove All Adjacent Duplicates In String # 题目 # Given a string S of lowercase letters, a duplicate removal consists of choosing two adjacent and equal letters, and removing them. We repeatedly make duplicate removals on S until we no longer can
Return the final string after all such duplicate removals have been made. It is guaranteed that the answer is unique. Example 1: Input: s = "abcd", k = 2 Output: "abcd" Explanation: There's nothing to delete. 1. 2. 3. Example 2: ...
1047.Remove All Adjacent Duplicates In String Given a stringSof lowercase letters, aduplicate removalconsists of choosing two adjacent and equal letters, and removing them. We repeatedly make duplicate removals on S until we no longer can.
Can you solve this real interview question? Remove Linked List Elements - Given the head of a linked list and an integer val, remove all the nodes of the linked list that has Node.val == val, and return the new head. Example 1: [https://assets.leetc
最后栈中的元素需要按匹配成功次数还原才是答案:例如: [s, c], [2, 1]。 答案应该是ssc。 classSolution:defremoveDuplicates(self,s:str,k:int)->str:num_st=[]cnt_st=[]foriinrange(len(s)):ifnotnum_stornum_st[-1]!=s[i]:num_st.append(s[i])cnt_st.append(1)else:cnt_st[-1]+=1...