end()函数返回一个std::sregex_token_iterator对象,表示迭代器的结束位置。 最后,我们可以将end()函数返回的迭代器作为end模板参数传递给regex_token_iterator,以指定迭代器的结束位置。 综上所述,推导开始regex_token_iterator上的end模板参数的过程包括获取输入字符串的长度、初始化迭代器并使用end()函数...
#include <regex> #include <iostream> typedef std::regex_token_iterator<const char *> Myiter; int main() { const char *pat = "aaxaayaaz"; Myiter::regex_type rx("(a)a"); Myiter next(pat, pat + strlen(pat), rx); Myiter end; // show whole match for (; next != end; ++nex...
end(), reg, // regex {0,2}); // 0: full match 2:second substring sregex_token_iterator end; for(;spos != end;++spos){ cout << "match: " << spos->str() << endl; } string names = "nico,jim,helmut,paul,tim,john,paul,rita"; regex sep("[ \t\n]*[,;:][ \t\n]*...
cin.get();return0; } 2.符号的拆分,如sregex_token_iterator 可以进行循环的拆分 intmain() { regex reg("\\s*[,#,:]+\\s*");//char str[100] = {0};stringstr;//123, 123, 123,getline(cin, str);//迭代器sregex_token_iterator end;//拆分字符串vector<string>myv;for(sregex_token_i...
首先，让我们从一个简单的示例开始，展示sregex_token_iterator函数的用法。cpp #include <iostream> #include <regex> int main() { std::string str = "Hello, World! This is a sample string.";std::regex pattern("\\s");std::sregex_token_iterator it(str.begin(), str.end(),pattern, -1)...
std::sregex_token_iterator end; while (iterator != end) { std::cout << *iterator << std::endl; ++iterator; } return 0; } 在上面的示例中,我们首先定义了一个包含水果名称的字符串fruits。然后,我们定义了一个正则表达式模式delimiter,用逗号作为分隔符。接下来,我们创建了一个sregex_token_iterator...
(), text.end(), ws_re,-1), std::sregex_token_iterator(),std::ostream_iterator<std::string>(std::cout,"\n"));std::cout<<'\n';// Iterating the first submatchesconststd::stringhtml=R"(google )"R"(< a HREF ="http://cppreference.com">cppreference\n)";conststd::regexurl_...
= end; ++next) std::cout << "match == " << next->str() << std::endl; std::cout << std::endl; // show prefixes and submatches std::vector<int> vec; vec.push_back(-1); vec.push_back(1); next = Myiter(pat, pat + strlen(pat), rx, vec); for (; next != end; ...
问用std::sregex_token_iterator实现std::transform的lambda(参数)中的const限定符EN在 C++ 标准库中，...
Two regex token iterators are equal if: a) They are both end-of-sequence iterators.b) They are both suffix iterators and the suffixes are equal.c) Neither of them is end-of-sequence or suffix iterator and:position == other.position N == other.N subs == other.subs 1...