字符串表达式如下：“match zero or more spaces provided they are not being preceded by a space or...
The*symbol can be used with the meta character.to match any string of characters.*. The*symbol can be used with the whitespace character\sto match a string of whitespace characters. For example, the expression\s*cat\s*means: zero or more spaces, followed by a lowercasec, followed by a ...
Not sure if that's a bug or not, but you can perfectly use " *?" to search for zero or more spaces (I always try to use lazy search when possible, if that's not your case remove the question mark after star), I have put that inside quotes to denote the space before the star....
Zero or more of a a* One or more of a a+ Exactly 3 of a a{3} 3 or more of a a{3,} Between 3 and 6 of a a{3,6} Start of string ^ End of string $ A word boundary \b Non-word boundary \B Regular Expression 105 matches (13,807 steps, 8.01ms) r" ([a-z]\s*)...
For example, the expression \s*cat\s* means: zero or more spaces, followed by a lowercase c, followed by a lowercase a, followed by a lowercase t, followed by zero or more spaces."\s*cat\s*" => The fat cat sat on the concatenation. ...
From the start of a string ^, we match zero or more non-space characters [^ ]* that are immediately followed by one or more spaces " +". The last part is added to prevent potential leading spaces in the results. To remove text before first space in each line, the formula is written...
*symbol can be used with the whitespace character\sto match a string of whitespace characters. For example, the expression\s*cat\s*means: zero or more spaces, followed by lowercase characterc, followed by lowercase charactera, followed by lowercase charactert, followed by zero or more spaces....
Zero or one of a a? Zero or more of a a* One or more of a a+ Exactly 3 of a a{3} 3 or more of a a{3,} Between 3 and 6 of a a{3,6} Start of string ^ End of string $ A word boundary \b Non-word boundary \B Regular Expression 1 match (54.86ms) @" ^(?:(?
*Zero or more occurrences"he.*o"Try it » +One or more occurrences"he.+o"Try it » ?Zero or one occurrences"he.?o"Try it » {}Exactly the specified number of occurrences"he.{2}o"Try it » |Either or"falls|stays"Try it » ...
使用Regex定位换行符前的空白您的代码所做的是匹配'%'或'之后的所有内容！'，然后替换字符串末尾的空格...