submatchall := re.FindAllString(str1, -1) for _, element := range submatchall { element = strings.Trim(element, "[") element = strings.Trim(element, "]") fmt.Println(element) } } 输出 Pattern: \[([^\[\]]*)\] Matched: true Text between square brackets: sample string SOME 用...
Please pay attention that our capturing group (.*?) performs alazy searchfor text between two brackets - from the first [ to the first ]. A capturing group without a question mark (.*) would do agreedy searchand capture everything from the first [ to the last ]. With the pattern in...
text1 text2 (with brackets) text3 (with brackets) text4 text5 t(with brackets)Tools Replace List Details Explain Roll-over elements below to highlight in the Expression above. Click to open in Reference. ^ Beginning. Matches the beginning of the string, or the beginning of a line if ...
?matches the previous token betweenzeroandonetimes, as many times as possible, giving back as needed(greedy) 2nd Capturing Group ([\w\-]+)? ?matches the previous token betweenzeroandonetimes, as many times as possible, giving back as needed(greedy) ...
Pattern: \[([^\[\]]*)\] Matched: true Text between square brackets: sample string SOME Regular expression to extract all Non-Alphanumeric Characters from a String Example package main import ( "fmt" "regexp" ) func main() { str1 := "We @@@Love@@@ #Go!$! ***Programming***Lang...
围绕第一个匹配项['"]创建一个组（(...)），然后在以后引用它(['"])(.*?)\1 ...
\ acts as an escape character that cancels the special meaning of the following character and turns it into a literal character. So, to find a bracket, you prefix it with a backslash: \[ to match an opening bracket and \] to match a closing bracket. Between the brackets, place a (cap...
RegEx is not necessarily as complicated as it first seems. What looks like an assorted mess of random characters can be over facing, but in reality it only takes a little reading to be able to use some basic Regular Expressions in your day to day work.
围绕第一个匹配项['"]创建一个组（(...)），然后在以后引用它(['"])(.*?)\1 ...
要在Python中正确地使用正则表达式删除嵌套括号，可以在while块中使用re.subn，使用简单的\([^()]*\)...