代码 #include<iostream>intfibonacci(intn){if(n==0)return0;// 基准条件if(n==1)return1;// 基准条件returnfibonacci(n-1)+fibonacci(n-2);// 递归调用}intmain(){intn=6;std::cout<<"Fibonacci of "<<n<<" is "<<fibonacci(n)<<std::endl;return0;} 递归过程分析 当n = 6时,递归调用...
二、Fibonacci数列(递归和非递归实现) Fibonacci
} } 当n比较大时,可以明显感觉算法运行速度比较慢,这是由于上述返回代码中使用了两层递归,使用递归的思想是好的,但是这里我们可以用迭代明显改善算法运行效率,用空间换时间。 publicclassSolution {publicintFibonacci(intn) {if(n < 2)returnn;intf = 0, g = 1;intresult = 0;for(inti = 1; i < n;...
这是代码: class qual { public static int fibonacci(int n) { if (n == 0 || n == 1) { return 1; } else { return fibonacci(n-1) + fibonacci(n-2); } } public static void main(String[] arg) { System.out.println(fibonacci(5)); } }Run Code Online (Sandbox Code Playgroud)...
As an example, consider computing the sequence of Fibonacci numbers, in which each number is the sum of the preceding two. def fib(n): if n == 0: return 0 if n == 1: return 1 else: return fib(n-2) + fib(n-1) Base case: What’s the simplest input I can give to fib? If...
If we wanted to implement this in Java, we’d write: publicintpowerOf10(intn){if(n ==0) {return1; }returnpowerOf10(n-1) *10; } 3.2. Finding N-Th Element of Fibonacci Sequence Starting with0and1,theFibonacci Sequenceis a sequence of numbers where each number is defined as the su...
} //非递归求fibonacci的值(迭代) publicstaticintnoRecursionFibonacci(intn){ if(n==1||n==2){ return1; } intf1 = 1; intf2 = 1; intf3 = 1; for(inti=0;i<n-2;i++){ f3 = f2+f1; f1=f2; f2=f3; } returnf3; } }
public class RecursiveFibonnaciJavaProgram { public static void main (String args[]) { for(long i=1; i<=9; i++){ System.out.print(fibonacci(i) +" "); } System.out.println(); }/* A recursive Fibonnaci sequence in Java program */public static longfibonacci(long number) { ...
Enter the number of values to be printed from the fibonacci series: 10 0 1 1 2 3 5 8 13 21 34 Dry run of the programi Output 0 0 1 1 2 return ( fib(2-1) + fib(2-2)) return ( fib(1) + fib(0)) return ( 1 + 0) = 1 therefore, fib(2) = 1 3 return ( fib(3-...
递归Recursion——Fibonacci 题目是构建一个Fibonacci数列 这是原来自己写的代码: k = int(input("Which term? ")) #输入要寻找的数 count = 2 # 计数 next_num = 0 #原始的Fibonacci函数里的数 if int(k) <= 2: #当数是F1和F2的时候就直接print1 print(1) el... ...