image_dataset_metadata::box box = data.images[i].boxes[k];// ignore boxes outside the cropped imageif(crop_rect.intersect(box.rect).area() ==0)continue;// mark boxes we include in the crop as ignored. Also mark boxes that// aren't totally within the crop as ignored.if(crop_rect....
初始化为 0 ,表示不相交,方便后续处理y:int=0# 如果 y 方向相交,则更新相交长度ifay1<=by2andby1<=ay2:y=min(ay2,by2)-max(ay1,by1)# 总面积 = 两个矩形的面积和 - 两个矩形重叠区域的面积returnSolution.area(ax1,ay1,ax2,ay2)+Solution.area(bx1,by1,bx2,by2)-x*y# 计算矩形(左下角为...
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publicclassSolution {publicstaticintcomputeArea(intA,intB,intC,intD,intE,intF,intG,intH) {intt1 = Math.max(A, E), t2 = Math.max(B, F), t3 = Math.min(C, G), t4 =Math.min(D, H);intarea1 =getArea(A, B, C, D);intarea2 =getArea(E, F, G, H);intarea3 =getArea(t1,...
223. Rectangle Area 题目描述(中等难度) 求出被两个矩形覆盖的面积。 解法一 这道题没有特殊的算法,就是对题目的分析,下边是我的思路。 首先将问题简单化,考虑如果没有重叠区域呢? 把两个矩形叫做 A 和 B,不重叠就有四种情况,A 在 B 左边,A 在 B 右边,A 在 B 上边,A 在 B 下边。
Rectangle Area Calculator. Find the length, width & diagonal of rectangle with our free to use calculator. Fantastic math tool.
【LeetCode】223. Rectangle Area 解题小结 题目: Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of...
A rectangle is a four-sided polygon that has its opposite sides equal in length. All the 4 angles are 90 degrees. A rectangle is a two-dimensional flat shape. Area and perimeter of rectangle at BYJU’S
The area of a rectangle ABCD is the total number of unit squares contained within it.Thus, the total area of the rectangle ABCD is 48 sq. inch. Also, using this approach, we find that the area of a rectangle is always the product of its two sides. Here, the length of AB is 8 ...
largestRectangleArea 单调栈 单调栈有什么用 什么是单调栈 单调递增栈:单调递增栈就是从栈底到栈顶数据是从大到小 单调递减栈:单调递减栈就是从栈底到栈顶数据是从小到大 解决那类问题 要知道单调栈的适用于解决什么样的问题,我们首先需要知道单调栈的作用。单调栈分为单调递增栈和单调递减栈,通过使用单调栈...