使用readline-sync时计时器不工作是因为readline-sync会阻塞JavaScript的事件循环,导致计时器无法正常工作。readline-sync是一个用于同步读取用户输入的模块,它会等待用户输入完成后才会继续执行后续代码。 解决这个问题的方法是使用异步的方式来读取用户输入,可以使用Node.js的内置模块readline来实现。下面是一个示例代码: ...
readlineSync是一个同步的包,可以通过简单的步骤在Node.js中使用。 以下是在Node.js上使用readlineSync的步骤: 步骤1:安装readlineSync包在终端中进入项目所在目录,运行以下命令安装readlineSync包: 代码语言:txt 复制 npm install readline-sync 步骤2:引入readlineSync包在你的Node.js文件中,使用以下代码引入readline...
readlineSync Synchronous Readline for interactively running to have a conversation with the user via a console(TTY). readlineSync tries to let your script have a conversation with the user via a console, even when the input/output stream is redirected like your-script <foo.dat >bar.log. Basic...
Synchronous Readline for interactively running to have a conversation with the user via a console(TTY). - anseki/readline-sync
const rls = require('readline-sync') console.log('你好') rls.question('你好') results λ node test.js 你好 浣犲ソ I'm on I'm on windows 7, node 6.2.1.
步骤2:创建readlineSync对象 接下来,我们需要使用readlineSync模块创建一个readlineSync对象。这个对象将用于与用户进行交互。以下是创建readlineSync对象的代码: AI检测代码解析 constreadline=readlineSync.createInterface({input:process.stdin,output:process.stdout}); ...
Nodejs readlinesync question 输入乱码 nodejs readstream,阅读目录一:nodeJS中的stream(流)的概念及作用?二:fs.createReadStream()可读流三:fs.createWriteStream()可写流回到顶部一:nodeJS中的stream(流)的概念及作用?什么是流呢?日常生活中有水流,我们很容易想
TypeScript definitions for readline-sync. Latest version: 1.4.8, last published: a year ago. Start using @types/readline-sync in your project by running `npm i @types/readline-sync`. There are 107 other projects in the npm registry using @types/readline-
1 //普通读取方法 2 // var data = fs.readFileSync(versionpath,'utf8'); 3 // var dataarr = data.split('\n'); 4 // dataarr.forEach(function(dataarr) { 5 // if( dataarr.indexOf('version') > -1) { 6 // version = (dataarr.split(':')[1]).match(/\"(.*)\"/)[1]...
});fs.writeFileSync('./package.json',JSON.stringify(map,null,4)); }functionrunQuestionLoop() {if(index===questions.length) {createPackageJson();rl.close();return; }let defaultAnswer= defaultAnswers[index];let question= questions[index]+': ('+ defaultAnswer+')';rl.question(question,func...