While it is difficult to predict the exact marks required to secure a specific rank in the JEE Advanced, we can make some general observations. As the ranks increase, the marks required tend to decrease. This is because the top ranks are usually achieved by a smaller pool of candidates who...
Ans: With JEE Main marks of 100, 85-95 percentile can be calculated. A JEE Main score of 85-95 percentile is recognised to be ideal for getting into one of the NITs and IITs. Q: Is the 40 percentile enough for JEE Advanced? Ans: The expected cut-off percentile of the general categ...
JEE Advanced Rank List 2025: IIT Guwahati will release the JEE Advanced rank list 2025 online on its official website after the JEE Advanced result declaration. The authorities will consider the candidates’ marks in JEE Advanced to prepare the rank list. It will also release the criteria for ...
The result has been released for JEE Advanced 2022 on September 11.Share JEE Advanced Topper 2022 – The result has been released for JEE Advanced 2022 on September 11. JEE Advanced 2022 result consists of the marks secured by the candidate in the exam along with their qualifying status. The...
TANCET 2024 Cut Off Marks TANCET Contact Details TANCET 2024 counselling registration for MBA and MCA admission has been concluded. As a part of the TANCET counselling 2024 process, Anna University will release the MBA and MCA program rank lists will on Jul 22, 2024. If there are any anomalie...
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The National Testing Agency (NTA) will release the category-wise cutoff marks for JEE Main 2025 online along with the results. The cutoff marks, which represent the minimum score required to qualify for the JEE Advanced exam, are determined based on the difficulty of the questions and the NTA...
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Percentage:One must have scored at least75% marksin the qualifying exam. Age Limit:To be eligible, candidates must be born on or after1st October, 1999. Rank:One must have validJEE Main rank. Appearing: Candidatesappearingin the qualifying examination will bealso eligibleto apply. ...
IIT JEE Entrance Exam 0 Answer Available Last Activity: 2 Years ago Can class 9th students study syllabus classof 11th IIT JEE Entrance Exam 3 Answer Available Last Activity: 2 Years ago Sum of series 2[n/2] ! [n/2]!/ n! [2Co-2C2+3C2...+[-1]^n[n+1]2Cn] where n is an ...