vector<vector<int>>colSum; }; Github 同步地址: https://github.com/grandyang/leetcode/issues/308 类似题目: Range Sum Query 2D - Immutable Range Sum Query - Mutable Range Sum Query - Immutable 参考资料: https://leetcode.com/problems/range-sum-query-2d-mutable/ https://leetcode.com/problem...
Binary Indexed Tree is represented as an array. Let the array be BITree[]. Each node of Binary Indexed Tree stores sum of some elements of given array. Size of Binary Indexed Tree is equal to n where n is size of input array. In the below code, wehave used size as n+1 for ease...
sum+=d;returnd; }longlongget(intrx0,intry0,intrx1,intry1) {if(rx0 == x0 && rx1 == x1 && ry0 == y0 && ry1 ==y1) {returnsum; }//intxmid =getMidX();intymid =getMidY();longlongd =0;if(rx0 <= xmid && ry0 <=ymid) { d+= ul->get(rx0, ry0, min(xmid, rx...
Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2). Range Sum Query 2D The above rectangle (with the red border) is defined by (row1, col1) = (2, 1) and (row2, col2...
Leetcode: Range Sum Query 2D - Mutable && Summary: Binary Indexed Tree,参考:https://leetcode.com/discuss/72685/share-my-java-2-d-binary-indexed-tree-solutionBuildbinaryindexedtreetakes:O(mn*logm*logn)time,both upda
Range Sum Query 2D - Mutable Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2). The above rectangle (with the red border) is defined by (row1, col1) = (2, 1) and (...
cpp Copy code class NumMatrix { public: vector<vector> pre_sum; NumMatrix(vector<vector<int>>& matrix) { // Check if the input matrix is empty if (matrix.empty() || matrix[0].empty()) return; int m = matrix.size(); int n = matrix[0].size(); ...
Given a 2D matrixmatrix, handle multiple queries of the following type: Calculate thesumof the elements ofmatrixinside the rectangle defined by itsupper left corner(row1, col1)andlower right corner(row2, col2). Implement theNumMatrixclass: ...
2 建立一个累积区域和的数组,从(r1, c1)到(r2, c2)区域的和为dp[r2][c2]-dp[r2][c1-1]-dp[r1-1][c2]+dp[r1-1][c1-1] 3 使用动态规划的时候,需要先initialize一个和原始matrix一样大小的matrix,其中每一个元素的值为0 4在init函数里,需要把每一个累积和求出来,这样在sumRegion函数里,就只需...
:pencil: Python / C++ 11 Solutions of All 411 LeetCode Questions - LeetCode-1/range-sum-query-2d-immutable.cpp at master · inspiron221/LeetCode-1