FCC结构的镍原子半径为0.1243 nm,试求镍的晶格参数和密度。Radius of Ni atom in FCC structure is 0.1243 nm, please calculate the lattice parameter and density of Ni. 相关知识点: 试题来源: 解析 答:FCC为面心立方结构,其中 4R=√2a⇒a=4/(√2)R 已知R=0.124
In subject area:Engineering More specifically, the effective radius of an atom is defined as the radius of a corresponding spherical ion having the same ΔGel as would the same molecule with partial charges set to zero for all atoms except the atom of interest. ...
Gold (atomic mass = 197 u) has atomic radius = 0.144 nm. It crystallises in face centred unit cell. Calculate the density of gold. (No = 6.022×1023mol−1) View Solution The radius of an atom of an element is 500 pm. If it crystallizes as a face-centred cubic lattice, what is...
Atom | Definition, Composition & Examples from Chapter 2/ Lesson 1 269K Learn the definition of an atom, what atoms contain, the nucleus in the middle of an atom, what atoms look like, and examples of atoms. Related to this Question ...
Consider a spherical cavity of radius R with an internal gas pressure of p. To obtain the local equilibrium vacancy concentration, we take one atom from the cavity surface and place it in one of the vacancies in the crystal lattice next to the cavity surface. The cavity volume is thereby ...
View Solution Excitation energy of hydrogen atom is 13.6eV. Match the following . View Solution The energy of hydrogen atom in its ground state is -13.6 eV , the energy of the level corresponding to n=7 is View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solut...
Why do the atomic and ionic radius of group three elements reduce across the period? The radius of the Ca atom is 0.197 nm, and the radius of the Ca2+ ion is 0.099 nm. Why is there a difference? Which of the following is the orbital radius of ...
Atom Radius Radio atómico KDE40.1 So now he's going to have an atomic radius that's actually much more similar to neon here, right? Entonces, va a quedar con un radio atómico que será mucho mas parecido al neon, cierto? QED (b) What is the atomic radius of silver in this...
This is partly because the external vestibule and the selectivity filters are experimentally more accessible, and also because of the low variance in atom's space coordinates among different K-channels across diverse crystallization conditions2–6. Thus, the structure of the external vestibule together...
characterized in that the adsorption agent has an average adsorption pore diameter of between 0.1 and 0.4 nm, and the phases of pressure build-up, adsorption, and regeneration are undergone in preferably four adsorbers arranged in parallel, the pressure build-up taking place first by pressure equa...