1.已知:P4(s,白磷)+502(g)=P4O10(s)△H P(s,红磷 )+5/4 0.(g)-1/4 Pa01n(s) )+ rac{5}{4}0.g)- rac{1}{4}{P}_{a}^{}{0}_{1n}^{}(s)( P4O10(s)△H2 设计成如下转化路径,请填空 P(白磷)~△H 4P(s,红磷) △H1 4△H2 P4O10(S) 则△H= ...