Pseudocode for Partition() in C The following is the pseudocode for partition() algorithm in C when the last element of the array is the pivot element. partition (array[], low, high) { pivot = array[high]; i = (low - 1) // Indicates the index of the smaller element and the right...
In order to achieve this partition, the pivot would have to be the median of the entire input; unfortunately this is hard to calculate and would consume much of the time, slowing down the algorithm considerably. A decent estimate can be obtained by choosing three elements randomly and using ...
Input Array: [4 6 3 2 1 9 7 ] === pivot swapped :9,7 Updated Array: [4 6 3 2 1 7 9 ] pivot swapped :4,1 Updated Array: [1 6 3 2 4 7 9 ] item swapped :6,2 pivot swapped :6,4 Updated Array: [1 2 3 4 6 7 9 ] pivot swapped :3,3 Updated Array: [1 2 3 ...
-> Yes: go to next block (0) (1) (2)← (0) (1) (2) [ 0a ][ 0b ][ 0c ][ 1a ][ 1b ][ 1c ][ 1d ][ 1e ] └────┘ 2nd block == 2 ? -> Yes: finish In pseudocode: for each index from 0 to blocks.count - 1: current = blocks[index].decode() while ...