*/functionpop(){if(empty($this->stack2)) {while(!empty($this->stack1)) {$this->stack2[] =array_pop($this->stack1); } }returnarray_pop($this->stack2); }/** * Get the front element. *@returnInteger */functionpeek(){if(empty($this->stack2)) {while(!empty($this->stack1)...
ArrayQueue.h #ifndef ARRAY_QUEUE_HXX#define ARRAY_QUEUE_HXX#include<iostream>usingnamespacestd;template<classT>classArrayQueue{public:ArrayQueue();~ArrayQueue();voidadd(Tt);Tfront();Tpop();intsize();intis_empty();private:T*arr;intcount;};// 构造函数。创建“队列”,默认大小是12template<...
这里采取第一种比较笨的方法,代码如下所示: 1classQueue {2public:3//Push element x to the back of queue.4voidpush(intx) {5s1.push(x);6}78//Removes the element from in front of queue.9voidpop(void) {10while(!s1.empty()){11s2.push(s1.top());12s1.pop();13}14s2.pop();15wh...
数据结构与算法(三)队列与堆(Queue and Heap) 队列(queue) 堆(Heap) 堆排序(Heapsort) LeetCode思想实践: 队列(queue) 基本FIFO队列是先进先出( First-In-First-Out)的线性表。在具体应用中通常用链表或者数组来实现。队列只允许在后端(称为rear)进行插入操作,在前端(称为front)进行删除操作。 除基本FIFO队列...
leetcode 697[easy]---Degree of an Array 难度:easy Given a non-empty array of non-negative integers nums, the degree of this array is defined as the maximum frequency of any one of its elements. Your task is to find the smallest... ...
Kth Largest Element in an Array leetcode 215 遍历数组 创建pq 直接 往pq中插入数字 当数字容量大于k的时候,弹出顶端元素,因为顶上面的元素最大 遍历完数组之后,留下来的就是 前k个最小数了 返回pq的顶上,就是 第 k个最小值 使用max heap 如果 元素容量超过 k了,我们就丢弃掉最大的那个 ...
Design Circular Queue https://leetcode.com/problems/design-circular-queue/discuss/149420/Concise-Java-using-array/167623https:///watch?v=Ig34WPrgofIdequeue doesn’t change the value at the top, it just moves the front pointer to the next one , and len- -. ...
几个重要操作这里我用python写了,以及由于我打算从数组下标0开始以及去掉qp(后面会解释),所以对于root,index=k, 其实左儿子为2k+1,右儿子为2k+2, 对于一个 index=k结点 ,parents的下标为(k-1),我的Python版本是去掉了qp的,我一开始以为可以简化,后来必现too yount too naive,大家在刷Leetcode不知道有没有...
Take(K).ToArray();It's time complexity is O(N Log N) where N is poins.Length.But this task is actually about Heap / PriorityQue which is not implemented in C#.Using Heap time complexity is O(N Log K). So it Is better if we need only 10 points from millions as we run th...
Code Issues Pull requests leetcode.com , algoexpert.io solutions in python and swift pythonswiftstackqueuealgorithmsleetcodegraphtriepython3binary-search-treeheaptree-structureleetcode-solutionsdynamic-programmingbinary-heapbinary-searchleetcode-pythonleetcode-swiftswift-5algoexpert ...