There areCqueries and for each query you are given two integersd(the node number) andeand you have to find the maximum value wheneis xor'ed with any of the ancestors ofdorditself. Formally, find the maximum value which can be obtained wheneis XOR'ed with any node in the path fromdto...
I had got this question in Cisco coding round. I would be grateful if anyone could provide an approach or even an hint. Problem statement is quite long ,please bear with me. Mr McFly has gone k number of Days into the past. He knows the prices of stocks in the stock market and how...
C# Parallel For Loop Problem - Object reference not set to an instance of an object C# Parallel-ForEach - shared state c# parse a textfile format key/value c# Password expired C# plugin Unable to load one or more of the requested types. Retrieve the LoaderExceptions property for more inform...
“coding” and “authoring test cases”) which both need to be completed before moving to the next state (e.g., “ready for QA”). If you think this practice smells a little bit siloed and waterfall-y anyway, I am inclined to agree. ...
TCS NQT will use TCS iON platform for their both Rounds, below you will find details: TCS NQTRound 1 (Foundation)Round 2 (Advance) Total no. of question 65 MCQ and Non-MCQ Type 15 MCQ and Non- MCQ and 3 Coding Questions Allotted Time 75 mins 115 mins Total Sections 3 sections Adva...
It is intended primarily for use with coding questions where the answerbox presents the students with code that has smallish bits missing, but it can also be used in non-coding questions. The locations within the globalextra text at which the input elements are to be inserted are denoted by...
combo_box.scrollPosition=Math.round(Math.min(combo_box.mouseY*m+b,combo_box.maxScrollPosition)); } function stopscrollF(e:Event):void{ this.removeEventListener(Event.ENTER_FRAME,scrollF); } function paramF(x1:Number,y1:Number,x2:Number,y2:Number):void{ m=(y1-y2)/(x1-x2); b=m*...
#coding:utf-8 from multiprocessing import Pool import os,time,random def worker(msg): t_start = time.time() print("%s 开始执行,进程号为%d"%(msg,os.getpid())) # random.random()随机生成0-1之间的浮点数 time.sleep(random.random()*2) t_stop = time.time() print(msg,"执行完毕,耗时%...
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Hello Everyone, I recently encountered this problem in an Interview. You are given N. You have to construct an array of 2*N size with conditions: You have to use a number from 1 to N that means each number must be used exactly twice. ...