Queries for the Array 题解 前言这场CF 是我赛后打的,vp 赛时没做出来,后来发现是有个地方理解错了,有一些细节没有考虑到。现在换了一种思路来写,感觉更清晰了。做法首先需要动态维护三个变量,cntcnt 和finishsortfinishsort 和unfinishsortunfinishsort。这三个变量分别表示当前数字的个数,已经排好序的最后一...
AC代码: 1#include<cstdio>2intans[100100][501];3inta[100100];4intk,n,q,p;5intget(intx)6{7if(x>n)8return0;9if(ans[x][k])returnans[x][k];10returnans[x][k]=get(x+a[x]+k)+1;11}12intget2(intx)13{14if(x>n)15return0;16else17returnget2(x+a[x]+k)+1;18}19intm...
Codeforces-1114F:Please, another Queries on Array?(线段树) F. Please, another Queries on Array? time limit per test 5.5 seconds memory limit per test 256 megabytes input standard input output standard output You are given an array a1,a2,…,an.a_1,a_2,&h......
#include <vector> #define rep(i,x,n) for(int i=x;i<n;i++) #define repd(i,x,n) for(int i=x;i<=n;i++) #define pii pair<int,int> #define pll pair<long long ,long long> #define gbtb std::ios::sync_with_stdio(false) #define MS0(X) memset((X), 0, sizeof((X))...
step accross left, right, up or down respectively. Bob lives in a house having coordinates (Stx, Sty)(1-Based indexing). You are given Q tasks contains an integer X each. In each task, you have to find number of unique houses (including his house) can be travelled using the amount ...
logN)O(log2N). No, I don't think you need to merge maps — theposstructure wouldn't be inside the segment tree, it would be something that you build with the initial array and never change again. The update function should simply push lazy values down and update related nodes with th...
Codeforces Round #538 (Div. 2)F Please, another Queries on Array? (数论+线段树+状态压缩) 题目链接:http://codeforces.com/contest/1114 题目大意: 查询结构, 初始给定一个序列,支持两种操作, 一种是 在区间上每个数都乘上一个x, 一种是查询区间上每个数累乘后的结果的欧拉函数。 题目分析: 这道题...
All numbers in the input are integers. For each query to calculate the sum print an integer — the required sum modulo1000000007 (109 + 7). Input The first line contains two integersnandm(1 ≤ n, m ≤ 105), showing, how many numbers are in the array and the number ...
Ridbit has a hidden array a of n integers which he wants Ashish to guess. Note that n is a power of two. Ashish is allowed to ask three different types of queries. They are of the form AND i j: ask for the bitwise AND of elements ai and aj (1≤i,j≤n, i≠j) ...
Given an arrayaacontainingnnelements and you will haveqqqueries. Each query denote byll,rr,xx. You have to check if from indexlltorr, is there any element equal toxxor not. Contraint: nn,qq≤≤105105 11≤≤ll≤≤rr≤≤nn 11≤≤a1a1,a2a2,...,anan≤≤109109 ...