1.An arc equal to one quarter of the circumference of a circle; an arc of 90°. 2.Any of the four regions into which a plane is divided by the axes of a Cartesian coordinate system. The quadrants are numbered counterclockwise one through four, beginning with the quadrant in which both ...
The coordinates of the point (-2, 6) are negative on the x-axis and positive on the y-axis, thus it lies in the 2nd quadrant. The coordinate of the point (7, -4) are positive on the x-axis and negative on the y-axis, thus it lies in the 4th quadrant. ...
A(X−2)2+(y−2)2=(2)2 B(x+2)2+(y+2)2=4 C(x+2)2+(y+2)2=2 D(x−2)2+(y−2)2=2Submit The equation of the circle in the first quadrant touching each co-ordinate axis at a distance of one unit from the origing is : Ax2+y2−2x−2y+1=0 Bx2+y2−...
In trigonometry, the unit circle quadrants divide the 360 degrees unit circle into four-90 degrees parts known as the quadrants. The quadrants are named from the top right quadrant in an anticlockwise direction as I, II, III and IV. Answer and Explanation...
Identify the quadrant that θ lies in as OP moves around the unit circle and hence state whether the trigonometric function of θ is positive or negative.θ =-100^(° ), tan θ 相关知识点: 试题来源: 解析 3rd, positive 反馈 收藏 ...
From 1570s as "the quarter of a circle, the arc of a circle containing 90 degrees." The ancient surveying instrument for measuring altitudes is so called from c. 1400, because it forms a quarter circle. Related:Quadrantal. also fromlate 14c. ...
Find the area outside r = 3 - 2 \sin \theta and inside r = -3 + 2 \sin \theta. Find the exact value for sin(x + y) if sin x = -4/5 and cos y = 15/17. Angles x and y are in the fourth quadrant. If the point P (\frac{15}{17}, y...
15° is not a commonly known angle, and it doesn't usually appear on the unit circle. But 15 is half of 30, which is a common angle on the unit circle. Use the half-angle identity for sine. $$sin\:15^{\circ}=\sqrt{\frac{1-cos\:30^{\circ}}{2}} $$ ...
Find the opposite side of theunit circletriangle. Since the adjacent side andhypotenuseare known, use thePythagorean theoremto find the remaining side. Opposite=√hypotenuse2−adjacent2Opposite=hypotenuse2-adjacent2 Replace the known values in theequation. ...
Find the opposite side of the unit circletriangle. Since the adjacent side and hypotenuse are known, use the Pythagorean theorem to find the remaining side.( (Opposite)=√(((hypotenuse))^2-((adjacent))^2))Replace the known values in the equation.( (Opposite)=√(((5))^2-((1))^...