1. 解释错误消息 "qtablewidget: cannot insert an item that is already owned by another qtablew" 的含义 这个错误消息表明你尝试将一个已经属于另一个 QTableWidget 的项(比如 QTableWidgetItem)插入到当前的 QTableWidget 中。在 Qt 的模型/视图架构中,每个项(item)只能属于一个父对象(在这个上下文中是 QTable...
qt程序,Debug编译正常运行,Release运行时程序起不来,发现输出信息中有错误QTableWidget: cannot insert an item that is already owned by another QTableWidget提示。调试了两三天才解决。 之前以为这个错误肯定是QTableWidget有关的错误,由于运行时错误难以调试,只能全局搜索QTableWidget,QT... 查看原文 QTableWidget和QTabl...
Qt获得日志消息: (venv) PS C:\application> python .\main.py QTableWidget: cannot insert an item that is already owned by another QTableWidget QTableWidget: cannot insert an item that is already owned by another QTableWidget ... 如果我在IDE中运行它,我就不会看到这些消息。 浏览7提问于2022-07-2...
QTableWidg..请教各位高手,程序一启动就奔溃,报cannot insert an item that is already owned QTableWidget错。昨天都还好好的,咋回事啊?cannot insert an item that already owned by other QTablewidget
# 需要导入模块: from PyQt4.QtGui import QTableWidget [as 别名]# 或者: from PyQt4.QtGui.QTableWidget importinsertRow[as 别名]defload_relation(self, filenames=[]):""" Load relation from file """importcsvfromPyQt4.QtGuiimportQTableWidgetItem, QTableWidgetfromsrc.coreimportrelationifnotfilenames...
self.connect(self.addEntry, SIGNAL("clicked()"), self.insertPattern) self.grid.addWidget(self.filetypeLabel,0,0) self.grid.addWidget(self.filetype,0,1,1,2) self.createPattern("Header",2) self.createPattern("Footer",3) self.grid.addWidget(self.windowLabel,4,0) ...
QTableWidgetItem是Qt框架中的一个类,用于在表格中显示和编辑数据。它提供了一些属性和方法来设置单元格的外观和行为。 在Qt中,QTableWidgetItem的背景色可以通过设置单元格的QBrush属性来实现。可以使用QTableWidgetItem的setBackground()方法来设置单元格的背景色。 以下是一个示例代码,演示如何设置QTableWidgetItem的背景...
QTableWidgetItem(str(task.name))) combo = QComboBox() items = [task_typefortask_typeinTask.task_types_names] combo.addItems(items)#FIXME:only until I get an access to the documentation.fori, tinenumerate(Task.task_types_names):ift == task.task_type: ...
self.user_list.insertRow(index) name_item = QTableWidgetItem(user.name) name_item.setFlags(name_item.flags() & ~Qt.ItemIsEditable) self.user_list.setItem(index,0, name_item) id_item = QTableWidgetItem(str(user.id)) id_item.setFlags(id_item.flags() & ~Qt.ItemIsEditable) ...
self.table.insertRow(row) self.table.setItem(row,0, key_item) self.table.setItem(row,1, value_item) row +=1self.table.blockSignals(blocked) 开发者ID:PETECLAM,项目名称:ResInsight,代码行数:92,代码来源:keyword_table.py 示例5: process ...