根据热量计算公式\(Q = c\times m\times\Delta t\)(其中\(c\)为比热容,\(m\)为质量,\(\Delta t\)为温度变化量)。 1. 首先计算质量\(m\): - 已知油的流量\(Q = 50t/h\),因为\(1t = 1000kg\),所以\(m = 50\times1000kg/h\)。 2. 然后计算温度变化量\(\Delta t\): - 入口油温\...
The idea of probabilistic q-rung orthopair linguistic neutrosophic (P-QROLN) is one of the very few reliable tools in computational intelligence. This paper explores a significant breakthrough in nanotechnology, highlighting the introduction of nanoparti
该题使用热量计算公式 Q = cmΔ t 求解。已知水的比热容 c = 4.2 * 10^3 \, (J/(kg) ⋅ (°C)),质量 m = 100 \, (kg),温度变化 Δ t = 75 \, (°C)。将这些值代入公式,得到 Q = 4.2 * 10^3 * 100 * 75 = 3.15 * 10^7 \, 。因此,水的热量为 3.15 * 10^7 \,...
Interactive help subsystem for the q/kdb+ session. Contribute to KxSystems/help development by creating an account on GitHub.
1.电流强度:I=q/t{I:电流强度(A),q:在时间t内通过导体横载面的电量(C),t:时间(s)} 2.欧姆定律:I=U/R {I:导体电流强度(A),U:导体两端电压(V),R:导体阻值(Ω)} 3.电阻、电阻定律:R=ρL/S{ρ:电阻率(Ω?m),L:导体的长度(m),S:导体横截面积(m2)} 4.闭合电路欧姆定律:I=E/(r+R)...
C Geweniger,S Gjesdal,F Vannucci,... - 《Bulletin of the Polish Academy of Sciences Mathematics》 被引量: 3发表: 1975年 $\\Delta M_{d,s}$, $B^0_{d,s}\\to\\mu^+\\mu^-$ and $B\\to X_s\\gamma$ in Supersymmetry at Large $\\tan\\beta$ We present an effective Lagrangian...
Fig. 1: Conceptual scheme of BQC. In the preparation stage of the BQC protocol, a client randomly prepares m qubits and sends them to a quantum server. The server uses the qubits to form a resource state for the computation. In the measurement stage, \({{{\mathcal{O}}}(m)\) roun...
4. Q_{吸}=cm\cdot {\Delta}t=4.2\times 10^{3}J/(kg\cdot ^{\circ}C)\times 3.5kg\times (70^{\circ}C-50^{\circ}C) 相关知识点: 试题来源: 解析 294000解:温度变化:△t=70-50=20(摄氏度) 热量:Q=cm⋅Δt=4.2*10^3*3.5*20=294000(焦耳) 所以,水吸收的热量是 294000焦耳...
The decay of the first two excited states of ${}^{17}\\mathrm{Ne}$ ${(I}^{\\ensuremath{\\pi}}={\\frac{3}{2}}^{\\ensuremath{-}},$ ${\\frac{5}{2}}^{\\ensurem... M. Chromik,P. Thirolf,M. Thoennessen,... - Physical Review C 被引量: 0发表: 2002年 ...
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