Python 3 has a built-in functioninput()to accept user input. But it doesn’t evaluate the data received from theinput()function, i.e., Theinput()function always converts the user input into a string and then returns it to the calling program. Check input is a number or a string in ...
a = int(input("Input a number: ")) # If successful, break out of the loop and continue with the next code. break except ValueError: # If the input is not a valid integer, an exception (ValueError) is raised. # In that case, print an error message and prompt the user to try aga...
The input from the user is treated as a string. Even if, in the example above, you can input a number, the Python interpreter will still treat it as a string.You can convert the input into a number with the float() function:
user_input = input("请选择以下选项(1-3):") if user_input in ['1', '2', '3']: print(f"你选择了选项{user_input}") break else: print("无效的输入,请重新选择") # 请选择以下选项(1-3):4 # 无效的输入,请重新选择 # 请选择以下选项(1-3):5 # 无效的输入,请重新选择 # 请选择以...
Create a lockfile containing pre-releases:$ pipenv lock--pre Show a graphofyour installed dependencies:$ pipenv graph Check your installed dependenciesforsecurity vulnerabilities:$ pipenv check Install a local setup.py into your virtual environment/Pipfile:$ pipenv install-e.Use a lower-level pip co...
user_input)Irrational_Number = replace_names_and_return_float(input("ENTER a Irrational Number : ...
>>> import pyinputplus as pyip >>> response = pyip.inputInt(prompt='Enter a number: ') Enter a number: cat 'cat' is not an integer. Enter a number: 42 >>> response 42 使用Python 的help()函数来了解关于这些函数的更多信息。例如,help(pyip.inputChoice)显示inputChoice()函数的帮助信息...
output = user_input or "没有输入内容" print(output) 在这个例子中,如果用户没有输入任何内容(input()返回空字符串) ,output就会被赋值为默认字符串"没有输入内容",展示了or作为默认值设定的优雅。 3.2 替代三元运算符的巧妙方案 虽然Python提供了简洁的三元运算符语法,但在某些场景下,利用and和or可以创造更为...
password1 = input('请输入密码:') password2 = input('请再次输入密码:') if password1 == password2: print('正确') else print('输入密码不一致') 1. 2. 3. 4. 5. 6. 3.用户密码复杂度验证 a.长度超过8位 这边直接用if判断句就行了,直接获取密码值,然后做一个if判断就行了 ...
1 def test(): 2 num = int(input('please enter a number:')) 3 if num % 2 == 0:#判断输入的数字是不是偶数 4 return True #如果是偶数的话,程序就退出了,返回True 5 print('不是偶数请重新输入!') 6 return test() #如果不是偶数的话继续调用自己,输入值 7 print(test()) #调用函数...