如果你的嵌套 list 结构更复杂,比如有更多层次的嵌套,那么你需要使用递归方法进行拆包。下面是一个简单的示例: defunpack_list(items):foriteminitems:ifisinstance(item,list):unpack_list(item)# 递归调用else:print(item)# 测试嵌套 listcomplex_nested_list=[1,[2,[3,4
You can also have nested lists and nested tuples or a combination of them, like a list of tuples.The most notable difference between lists and tuples is that lists are mutable, while tuples are immutable. This feature distinguishes them and drives their specific use cases....
45:11# 12 ~ 16 字节是 py 文件的大小print( struct.unpack("<I", data[12: 16])[]) # 22结果和我们分析的一样，前 16 字节是固定的，而 16 个字节往后就是 PyCodeObject 对象，并且是序列化之后的，因为该对象显然无法直接存在文件中。import marshalwith open("__pycache__/tools.cpython-312....
A Nested List x[0], x[2], and x[4] are strings, each one character long:>>> print(x[0], x[2], x[4]) a g j But x[1] and x[3] are sublists:>>> x[1] ['bb', ['ccc', 'ddd'], 'ee', 'ff'] >>> x[3] ['hh', 'ii'] ...
解压(unpack) 一维元组 (有几个元素左边括号定义几个变量) t = (1, 10.31, 'python') (a, b, c) = t print( a, b, c ) # 1 10.31 python 解压二维元组 (按照元组里的元组结构来定义变量) t = (1, 10.31, ('OK','python'))
a, b = b, a # 先生成一个元组(tuple)对象,然后unpack 1. 2. 3. 4. 5. 6. Unpacking ##不推荐 l = ['David', 'Pythonista', '+1-514-555-1234'] first_name = l[0] last_name = l[1] phone_number = l[2] ##推荐 l = ['David', 'Pythonista', '+1-514-555-1234'] ...
将数据读取回来的时候,可以利用函数struct.unpack(),代码很相似,基本就是上面写操作的逆序。如下: def read_polys(filename): with open(filename, 'rb') as f: # Read the header header = f.read(40) file_code, min_x, min_y, max_x, max_y, num_polys = struct.unpack('<iddddi', header)...
元组是 Python 对象的集合,跟列表十分相似。下面进行简单的对比。 列表与元组 1、python中的列表list是变量,而元组tuple是常量。 列表:是使用方括号[],元组:则是使用圆括号() 2、两者都可以使用索引读取值 列…
In theforloop in this example, you nestzip()insideenumerate(). This means that each time theforloop iterates,enumerate()yields a tuple with the first value as the count and the second value as another tuple containing the elements from the arguments tozip(). To unpack the nested structure...
当找到符合条件的tuple时,我们就需要存储这个tuple,在上面的问题一种我们提到了如何存储这个tuple,需要注意的是saved_items将传入一个list,我们使用*来拆包(python unpack语法,具体需要查阅相关资料) def _find_sum_by_pointer(self, nums, left_start, target, saved_items): """ 1. 使用双指针来寻找值 2. ...