My friend Bill had previously alerted me to the coolness of Pythonsets. However I hadn't found opportunity to use them until now. Here are three functions usingsets to remove duplicate entries from a list, find the intersection of two lists, and find the union of two lists. Note,sets wer...
以下是一些常见的集合运算符及其用途。 5.1 并集(Union) **|**:将两个集合合并,去除重复元素,形成新的集合。 set1={1,2,3}set2={3,4,5}union_set=set1|set2print(union_set)# 输出: {1, 2, 3, 4, 5} 5.2 交集(Intersection) **&**:找出两个集合共有的元素,形成新的集合。 intersection_set...
(*others) # 5、生成一个并集:set | other 或 S.union(*others) # 6、更新为并集:set |= other 或 S.update(*others) # 7、生成一个补集:set ^ other 或 S.symmetric_difference # 8、更新为补集:set ^= other 或 symmetric_difference_update(other) # 9、判断是否为子集:set <= other 或 ...
Theunion()method allows you to join a set with other data types, like lists or tuples. The result will be a set. Example Join a set with a tuple: x = {"a","b","c"} y = (1,2,3) z = x.union(y) print(z) Try it Yourself » ...
tuple1=('两点水','twowter','liangdianshui',123,456)tuple2='两点水','twowter','liangdianshui',123,456 创建空元组 代码语言:javascript 复制 tuple3=() 元组中只包含一个元素时,需要在元素后面添加逗号 代码语言:javascript 复制 tuple4=(123,) ...
set.union(*others) Where: set: The set on which theunion()method is called. others: One or more sets or iterables whose elements will be included in the union. Consider the following example, where we have two sets,set1andset2, and we want to join them using theunion()method: ...
1.是一个无序不重复元素集, 基本功能包括关系测试和消除重复元素. 集合对象还支持union(联合), intersection(交), difference(差)和sysmmetric difference(对称差集)等数学运算. 2.sets 支持 x in set, len(set),和 for x in set。作为一个无序的集合,sets不记录元素位置或者插入点。因此,sets不支持 indexi...
[1,2,3]+[3,4,5,'abc']# Connect two lists. 1. [1, 2, 3, 3, 4, 5, 'abc'] 1. (1,2,'c')+(5,)# Connect two tuples 1. (1, 2, 'c', 5) 1. 'chenjie'+'youge'# Connect two strings. 1. 'chenjieyouge'
list1 = ["one","two","three","five"] list2= ["one","three","two","four"] set(list1).union(set(list2)) 参考: https://stackoverflow.com/questions/9623114/check-if-two-unordered-lists-are-equal https://stackoverflow.com/questions/3847386/testing-if-a-list-contains-another-list-wit...
union(<coll.>) # Or: <set> | <set> <set> = <set>.intersection(<coll.>) # Or: <set> & <set> <set> = <set>.difference(<coll.>) # Or: <set> - <set> <set> = <set>.symmetric_difference(<coll.>) # Or: <set> ^ <set> <bool> = <set>.issubset(<coll.>) # Or: ...