Python provides built-in functions to find the intersection and union of two sets or lists. These functions areintersectionandunion. In this article, we will explore these functions and see how they can be used in various scenarios. Intersection Theintersectionfunction returns a new set or list ...
Union of more than two sets: Python Code: # Create a set 'setn1' with repeated elements, including 1, 2, 3, 4, and 5:setn1=set([1,1,2,3,4,5])# Create a set 'setn2' with elements including 1, 5, 6, 7, 8, and 9:setn2=set([1,5,6,7,8,9])# Create a set 'setn...
(*others) # 5、生成一个并集:set | other 或 S.union(*others) # 6、更新为并集:set |= other 或 S.update(*others) # 7、生成一个补集:set ^ other 或 S.symmetric_difference # 8、更新为补集:set ^= other 或 symmetric_difference_update(other) # 9、判断是否为子集:set <= other 或 ...
set3 = set1.union(set2) print(set3) Try it Yourself » You can use the|operator instead of theunion()method, and you will get the same result. Example Use|to join two sets: set1 = {"a","b","c"} set2 = {1,2,3} ...
union(rdd2) print(Union_RDD.collect()) print(rdd1.intersection(rdd2).collect()) print(rdd2.subtract(rdd1).collect()) # Return a new RDD containing the distinct elements in this RDD. print(Union_RDD.distinct().collect()) print(Union_RDD.distinct().glom().collect()) key-Value算子 ...
In [137]: a.union(b) Out[137]: {1, 2, 3, 4, 5, 6, 7, 8} In [138]: a | b Out[138]: {1, 2, 3, 4, 5, 6, 7, 8} 交集intersection 或者 & 交集的元素包含在两个集合中。可以用intersection或&运算符: In [139]: a.intersection(b) ...
# Do set union with | # 计算并集 filled_set | other_set # => # Do set difference with - # 计算差集 {1, 2, 3, 4} - {2, 3, 5} # => # Do set symmetric difference with ^ # 这个有点特殊,计算对称集,也就是去掉重复元素剩下的内容 ...
合并是取两个集合中不重复的元素。可以用union方法,或者|运算符: 交集的元素包含在两个集合中。可以用intersection或&运算符: 表3-1列出了常用的集合方法。 表3-1 Python的集合操作 所有逻辑集合操作都有另外原地实现方法,它可以直接用结果替代集合的内容。对于大的集合,这么做效率更高: ...
主要章节和小节重新按照如下逻辑划分: 一、Python基础 1 数字 2 字符串 3 列表 4 流程控制 5 编程风格 6 函数 7 输入和输出 8 数据结构 9 模块 10 错误和异常 11 类和对象 二、Python模块 1 时间模块 2 文件操作 3 常见迭代器 4 yield 用法 5 装饰
[1,2,3]+[3,4,5,'abc']# Connect two lists. 1. [1, 2, 3, 3, 4, 5, 'abc'] 1. (1,2,'c')+(5,)# Connect two tuples 1. (1, 2, 'c', 5) 1. 'chenjie'+'youge'# Connect two strings. 1. 'chenjieyouge'