from datetime import time, timedelta ## total_seconds function x = timedelta(minutes = 2*15) total = x.total_seconds() print("Total seconds in 30 minutes:", total) Output: Total seconds in 30 minutes: 1800.0 方法二:自定义一个函数 def convert(x): hours = x.components.hours minutes =...
在datetime模块中,我们可以使用timedelta类来表示时间间隔,通过timedelta类的total_seconds()方法来获取时间间隔的秒数。 示例代码 下面是一个简单的示例代码,演示了如何将一个时间字符串转换为秒数: fromdatetimeimportdatetimedeftime_to_seconds(time_str):time_obj=datetime.strptime(time_str,'%H:%M:%S')seconds=...
转换to_timedelta,然后将total_seconds和rsub设置为900: df = pd.DataFrame({'gameClock': ['7:52', '13:31']}) df['out'] = (pd.to_timedelta('00:'+df['gameClock']) .dt.total_seconds().rsub(900) .convert_dtypes() ) Alternatively: df['out'] = (pd.to_timedelta('00:'+df['g...
import datetime def convert_seconds(seconds): # 将秒转换为timedelta对象 duration = datetime.timedelta(seconds=seconds) # 计算天数、月数和小时数 days = duration.days months = days // 30 hours = duration.seconds // 3600 return months, days, hours # 测试 seconds = 86400 months, days, hours ...
datetime.timedelta(minutes=1), datetime.timedelta(hours=1), datetime.timedelta(days=1), datetime.timedelta(weeks=1), ]: print('{:15} = {:8} seconds'.format( str(delta), delta.total_seconds()) ) # 输出 # 0:00:00.000001 = 1e-06 seconds ...
minutes = (seconds // 60) % 60 seconds = seconds % 60 return days, hours, minutes, seconds 所以,把它放在一起: def store_timedelta_in_database(thingy, duration): seconds = dhms_to_seconds(*convert_timedelta(duration)) db.execute('INSERT INTO foo (thingy, duration) VALUES (?, ?)', ...
The python code to convert seconds into the preferred format using Datetime module is as follows: importdatetime n=10000000time_format=str(datetime.timedelta(seconds=n))print("Time in preferred format :-",time_format) Copy Output : Time in preferred format :- 115 days, 17:46:40 ...
#convert to seconds seconds = timediff.total_seconds() #Convert seconds to hours (there are 3600 seconds in an hour) hours = (timediff.seconds)/3600 #Show the total print(hours) The output should be: 747 This indicates that 747 hours have passed between timedate1 and timedate2 ...
from datetime import timedelta def convert2timedelta(s): """convert string, like 00:00:00, to timedelta""" tm = map(int, s.split(':')) return timedelta(hours=tm[0], minutes=tm[1], seconds=tm[2]) # convert to timedeltaPython3支持的操作很丰富,包括+, -, *, /, //, %, div...
ConvertedSec=str(datetime.timedelta(seconds=SecToConvert)) print("ConvertedResultsare:",ConvertedSec) 输出: 正如您在示例中所看到的,使用DateTime模块比divmod()函数更快更快捷。DateTime模块提供格式,有助于高效地自动执行任务。 在Python中使用时间模块将秒转换为小时、分钟和秒 Python提供了另一个模块Time,具有...