dt.time():获取time对象; dt.replace():传入指定的year或month或day或hour或minute或second或microsecond,生成一个新日期datetime对象,但不改变原有的datetime对象; dt.timetuple():返回时间元组struct_time格式的日期; dt.utctimetuple():返回时间元组struct_time格式的日期; # 这个没什么用 dt.toordinal():返回...
pd.Timestamp(int(time.time()), unit="s", tz="Asia/Shanghai") Timestamp('2022-04-22 16:51:25+0800', tz='Asia/Shanghai') 1. 2. 示例9: time.time()+ td.total_seconds() pd.Timestamp(int(time.time()+ td.total_seconds()),unit='s') #Timestamp('2022-04-27 09:38:11') 1...
total_seconds()是获取两个时间之间的总差。 datetime模块下面有三个类,date,time,datetime,下面datetime为例解释,date/time用法类似 import datetime # print(datetime.datetime.now()) #返回 2016-08-19 12:47:03.941925 #print(datetime.date.fromtimestamp(time.time()) ) # 时间戳直接转成日期格式 2016-08...
Local time in UTC format : time.struct_time(tm_year=2019, tm_mon=8, tm_mday=6, tm_hour=5, tm_min=44, tm_sec=11, tm_wday=1, tm_yday=218, tm_isdst=0) ———– Current Time in seconds : 1565068234.0 ———- Current Time in local format : Tue Aug 6 10:40:34 2019 ——...
time.perf_counter()-self.startprint("*"*17,"time cost","*"*17)print(str(cost.total_seconds...
day>>>fromdatetimeimportdate#时间对象,常用属性有hour, minute, second, microsecond, tzinfo(时区)>>>fromdatetimeimporttime#时间间隔,常用属性有weeks, days, hours, ...>>>fromdatetimeimporttimedelta#日期间隔,常用属性有years,months, weeks, days, hours ...>>>fromdateutilimportrelativedelta注意:此模块...
# 输出时间差的秒数seconds_diff=time_diff.total_seconds()print(f"两个时间的间隔为{seconds_diff}秒。") 1. 2. 3. 完整代码 综合以上步骤,我们得到的完整代码如下: fromdatetimeimportdatetime# 获取用户输入的时间字符串time1=input("请输入第一个时间(格式:YYYY-MM-DD HH:MM:SS):")time2=input("请...
dt = datetime.datetime.fromtimestamp(timestamp_a)- datetime.datetime.fromtimestamp(timestamp_b) print dt.days, dt.total_seconds() # Out: 1 110000.0 四. 获取前N天,或者后N天时间 datetime.timedelta([days[, seconds[, microseconds[, milliseconds[, minutes[, hours[, weeks]]]) 代码语言...
python3 进行字符串、日期、时间、时间戳相关转换 文章被收录于专栏:热爱IT 1、字符串转换成时间戳 2、 日期转换成时间戳
from math import floor recordings = list(np.random.rand(1000)) # an example of recording chronometer_start = 1670000000 #timestamp start_recording = 1673280570 #timestamp gap_in_seconds = start_recording - chronometer_start # given that the recordings are of 5 minutes each but with 2.5 minute...