代码(Python3) class Solution: def sumOfNumberAndReverse(self, num: int) -> bool: # 枚举 [0, num] 内的每个数 for i in range(num + 1): # 如果当前 i 满足题意,则直接返回 true if i + Solution.reverse(i) == num: return True # 此时表明无满足题意的数,直接返回 false return False...
def sum_of_list(numbers):这是函数的定义。它告诉 Python 你正在创建一个名为 sum_of_list 的函数，并且这个函数需要一个参数 numbers，用于传递列表。total = 0：这一行创建了一个变量 total，并将其初始化为零。这个变量将用于累积列表中的元素总和。for number in numbers:这是一个 for 循环，它遍历列表...
(type "yes" if you do)\n\n'second_question = 'Would you like to enter another number after this? (type "yes" if you do)\n'sum_of_numbers = 0counter = 0if input(first_question) == "yes" :  
sum_of_number = 0 #存储和的值 for i in range(0,101): sum_of_number+=i else:print("==循环结束==") print(sum_of_number) (2)求1-100间5和7的倍数之和 代码语言:javascript 代码运行次数:0 运行 AI代码解释 for i in range(1,101): if i%5==0 or i%7==0: sum+=i print(sum)...
然后用sum函数对100以内的奇数求和最后用print函数将求和结果打印出来 这行代码充分体现了Python 语言的简洁性!!! 代码运行效果: 方法二:for循坏 代码语言:javascript 代码运行次数:0 运行 AI代码解释 count=0fornumberinrange(100):ifnumber%2==0:continuecount+=numberprint(count) ...
three(number)的次数：add_three_calls = 0def add_three(number):"""Return *number* + 3.""" global add_three_calls print(f'Returning {number + 3}') add_three_calls += 1 return number + 3def num_calls(): """Return the number of times *add_three* was called."...
len(text.split()), # Number of words len(text), # Number of characters ] print(*counts, path) 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 文件内容被分配给text变量,并在接下来的两次计算中重复使用。程序的功能仍然相同: ...
real_trades = profits[profits > 0]print ("Number of trades", len(real_trades), round(100.0 * len(real_trades)/len(closes), 2),"%")print ("平均盈利： %", round(np.mean(real_trades) * 100, 2))loss_trades = profits[profits < 0]print ("Number of trades", len(loss_trades), ...
最后要讲到的re.sub()函数用来替换字符串里被匹配到的字串内容,类似于Word里面的替换功能,除此之外它还可以定义最大替换数(maximum number of replacement)来指定sub()函数所能替换的字串内容的数量,默认状态下为全部替换。re.sub()返回的值是字符串。 re.sub()函数的语法如下: a = re.match(pattern, replac...
Write a Python program to calculate sum of digits of a number. Pictorial Presentation: Sample Solution: Python Code: # Prompt the user to input a four-digit number and convert it to an integer.num=int(input("Input a four-digit number: "))# Extract the thousands digit (x).x=num//1000...