count(s, sub[, start[,end]]) -> int 返回字符串中sub在start到end间出现过的次数 expandtabs(s, tabsize=8) expandtabs(s [,tabsize]) -> string 将字符串中的tab键用N个空格代替,默认为8个 find(s, *args) find(s, sub [,start [,end]]) -> in 寻找字符串从start到end间,sub是否出现过。
print str[:-3] #截取从头开始到倒数第三个字符之前 print str[2] #截取第三个字符 print str[-1] #截取倒数第一个字符 print str[::-1] #创造一个与原字符串顺序相反的字符串 print str[-3:-1] #截取倒数第三位与倒数第一位之前的字符 print str[-3:] #截取倒数第三位到结尾 print str[:-5...
startswith() 方法用于检查字符串是否是以指定子字符串开头,如果是则返回 True,否则返回 False。如果参数 beg 和 end 指定值,则在指定范围内检查。 代码语言:javascript 复制 str.startswith(str,beg=0,end=len(string));#str--检测的字符串。 #beg--可选参数用于设置字符串检测的起始位置。 #end--可选参数...
S.find(substring, [start [,end]]) #可指范围查找子串,返回索引值,否则返回-1 S.rfind(substring,[start [,end]]) #反向查找 S.index(substring,[start [,end]]) #同find,只是找不到产生ValueError异常 S.rindex(substring,[start [,end]])#同上反向查找 S.count(substring,[start [,end]]) #返回...
python没有substring函数,因为直接使用str[start:end]就可以啦。字母处理 全部大写:str.upper()全部小写:str.lower()大小写互换:str.swapcase()首字母大写,其余小写:str.capitalize()首字母大写:str.title()print '%s lower=%s' % (str,str.lower())...
ValueError: substring not found >>> str.index("n") #同find类似,返回第一次匹配的索引值 4 >>> str.rindex("n") #返回最后一次匹配的索引值 11 >>> str.count('a') #字符串中匹配的次数 0 >>> str.count('n') #同上 2 >>> str.replace('EAR','ear') #匹配替换 'string learn' >...
subString: ectorA Explanation: Firstly, an original string is created. Secondly, a slicing operator is used in which startIndex and the endIndex syntax are passed. Finally, in the resulting output, the character at startIndex is included while the character at endIndex is excluded. ...
When you call len() with a string as an argument, you get the number of characters in the string at hand.Another common operation you’d run on strings is retrieving a single character or a substring from an existing string. In these situations, you can use indexing and slicing, ...
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ValueError: substring not fou 16、rindex() 描述:rindex() 方法返回子字符串最后一次出现在字符串中的索引位置,该方法与rfind()方法一样,可以规定字符串的索引查找范围[star,end),只不过如果子字符串不在字符串中会报一个异常。 语法:str.rindex(sub, start, end) -> int 返回整数。