所以,在此处a_string[18:]跟a_string[18:44]的结果是一样的,因为这个串的刚好有44个字符。这种规则存在某种有趣的对称性。在这个由44个字符组成的串中,a_string[:18]会返回前18个字符,而a_string[18:]则会返回除了前18个字符以外字符串的剩余部分。事实上a_string[:n]总是会返回串的前n个字符,而a_s...
Pythonslice()Function ❮ Built-in Functions ExampleGet your own Python Server Create a tuple and a slice object. Use the slice object to get only the two first items of the tuple: a = ("a","b","c","d","e","f","g","h") ...
截止到python版本3.6.2 ，python一共提供了68个内置函数，具体如下👇abs() dict() help() min() setattr()all() dir() hex() next() slice() any() divmod() id() object() sorted() ascii() enumerate() input() oct() staticmethod() bin(...
# Program to get a substring from the given stringpy_string ='Python'# stop = 3# contains 0, 1 and 2 indices slice_object = slice(3) print(py_string[slice_object])# Pyt# start = 1, stop = 6, step = 2# contains 1, 3 and 5 indicesslice_object = slice(1,6,2)print(py_stri...
“Remember that Python starts counting indexes from 0 not 1. Just like it does with the range function, it considers the range of values between the first and one less than last number. 2. Modifying strings: Apart from trying to access certain characters inside a string, we might want to...
string = str(123456) 3、列表 list():列表类型,将一个可迭代对象转换为列表 # 直接赋值,用中括号包裹,用逗号分隔元素 list1 = [1, 2, 3, 4, 5] # 可以利用range函数赋值 list2 = list(range(1, 10)) 4、元组 tuple():元组类型,将一个可迭代对象转换为元组 ...
First, you can use theslicing operator, colon ‘:’ inside the square brackets ‘[]’; the second method is theslice()function. This approach is usually used in the field of data analysis and manipulation. Let’s see how to perform string slicing in Python. ...
repr() 返回一个对象的string形式 s = "今天\n吃了%s顿\t饭" % 3 print(s)#今天# 吃了3顿 饭 print(repr(s)) # 原样输出,过滤掉转义字符 \n \t \r 不管百分号% #'今天\n吃了3顿\t饭' 2. 数据集合 字典:dict 创建一个字典 集合:set 创建一个集合 frozenset() 创建一个冻结的集合,冻结的...
slice slice是当你对Python可迭代对象进行切片时背后调用的方法。例如my_list[1:3]内部的1:3实际上创建了一个slice对象。也就是说my_list[1:3]实际上是my_list[slice(1,3)] 代码语言:javascript 代码运行次数:0 运行 AI代码解释 本文参与腾讯云自媒体同步曝光计划,分享自微信公众号。
slice() 列表的切片 lst ="你好啊" it = reversed(lst)# 不会改变原列表. 返回一个迭代器, 设计上的一个规则 print(list(it))#['啊', '好', '你'] lst = [1, 2, 3, 4, 5, 6, 7] print(lst[1:3:1])#[2,3] s = slice(1, 3, 1)# 切片...