deffind_substrings(string,substrings):positions=[]forsubstringinsubstrings:index=string.find(substring)positions.append(index)returnpositions# 示例用法string="This is a test string."substrings=["is","test","string"]positions=find_substrings(string,substrings)print(positions)# 输出:[2, 10, 17] ...
Index of substring or "Not found". Write a Python program to determine the index of a given string at which a certain substring starts. If the substring is not found in the given string return 'Not found'. Sample Solution: Python Code: # Function to find index of substring def find_Ind...
首先,我们需要定义一个名为String的类,该类将包含一个名为indexOf的方法。以下是实现的代码示例: classString:def__init__(self,value):self.value=valuedefindexOf(self,substring):returnself.value.find(substring) 1. 2. 3. 4. 5. 6. 在这个类中,我们首先定义了一个构造函数__init__,它接受一个字符...
Note that find() function returns the index position of the substring if it’s found, otherwise it returns -1. Count of Substring Occurrence We can usecount() functionto find the number of occurrences of a substring in the string. s = 'My Name is Pankaj' print('Substring count =', s...
Python String find() The find() method returns the lowest index of the substring if it is found in given string. If its is not found then it returns -1. Syntax : str.find(sub,start,end) Parameters : sub :It’s the substring which needs to be searched in the given string....
# find the index of isresult = text.index('is') print(result)# Output: 7 index() Syntax It's syntax is: str.index(sub[, start[, end]] ) index() Parameters Theindex()method takes three parameters: sub- substring to be searched in the stringstr. ...
find() Return Value Thefind()method returns an integer value: If the substring exists inside the string, it returns the index of the first occurence of the substring. If a substring doesn't exist inside the string, it returns-1. Working of find() method ...
The index method can’t return a number because the substring isn’t there, so we get a value error instead: In order to avoid thisTraceback Error, we can use the keywordinto check if a substring is contained in a string. In the case of Loops, it was used for iteration, whereas in...
count(sub[, start[, end]]) -> int Return the number of non-overlapping occurrences of substring sub in string S[start:end]. Optional arguments start and end are interpreted as in slice notation. """ return 0 def decode(self, encoding=None, errors=None): """ 解码 """ """ S....
in <module>ValueError: substring not found从Python手册string.find(s, sub[, start[, end]])返回s...