import re def extract_number(string): pattern = r'\D+(\d+)' match = re.search(pattern, string) if match: return match.group(1) else: return None # 示例用法 string = "abc123def456" number = extract_number(string) print(number) # 输出:123 在上述代码中,使用了re模块的search函数来搜...
接下来,我们定义一个函数,该函数将接收一段文本和一个字符串作为参数,并返回该字符串后面的数字: defextract_number(text,string):pattern=string+r'\s*([\d\.]+)'match=re.search(pattern,text)ifmatch:returnmatch.group(1)else:returnNone 1. 2. 3. 4. 5. 6. 7. 在这个函数中,我们首先将要提取的...
接下来,让我们用 Mermaid 语法表示这个过程的类图。 StringProcessor+extract_numbers(string)+increment_numbers(numbers)+replace_numbers(string, old_numbers, new_numbers) 解释:这个类图展示了StringProcessor类的方法,包括提取数字、进行自增和替换数字的操作。 甘特图 现在,我们使用 Mermaid 语法表示这个项目的甘特图...
先说两个库的优劣：一、Pdfplumber关于安装：pipinstallpdfplumber1. 提取pdf每一页的文本内容.extract_te...
('lang'='JAVA') package com.mypackage; import java.util.regex.Matcher; import java.util.regex.Pattern; public class Foo { final static Pattern compile = Pattern.compile(".*?([0-9]+).*"); public static String extractNumber(String input) { final Matcher m = compile.matcher(input); if...
('state', 'state', label='state')# Find similar matches for pairs of surname and address_1 using string similaritycompare_cl.string('surname', 'surname', threshold=0.85, label='surname')compare_cl.string('address_1', ...
So Python returns a new string to me. 我也可以使用负索引进行切片。 I can also do slicing using negative indices. 例如,如果我键入S,减去3,Python将给出该序列中的最后三个字符,即h、o和n。 So for example, if I type S, minus 3, Python will give me the last three characters in that sequ...
query: A string to match against choices: A list or dictionary of choices, suitable for use withextract(). processor: Optional function for transforming choices before matching.Seeextract(). scorer: Scoring function for extract(). score_cutoff: Optional argument for score threshold. If the best...
keyspecifies a function of one argument that is used to extract a comparison key from each list element:key=str.lower. The default value isNone. 使用参数key=str.lower 代码如下: defcase_insensitive_sort2(liststring):returnsorted(liststring,key = str.lower) ...
If the string does not hold any number, it is convenient to set the default value that would be returned in this case. PythonCopy Code def ExtractNumber(Strng, DefaultValue): reg = r"(\+?\-?\ *\d+\.?\d*(?:[Ee]\ *-?\ *\d+)?)" #Specify the regular expression MatchArr=re....