"# 使用find()方法获取字符"W"的索引index=str.find("W")ifindex!=-1:print("Character W is at index:",index)else:print("Character not found in string") 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 在上面的示例中,我们定义了一个字符串"Hello, World!",然后使用find()方法获取了字符"W"的索...
>>> string = " python " >>> string.replace('python','java') #将'python'替换成'java' ' java ' >>> string.strip() #去掉了两边的空格(空字符应该都可以,默认的) 'python' >>> string.rstrip() #去掉右边的空字符 ' python' >>> string.lstrip() #去掉左边的空字符 'python ' >>> stri...
We’re not changing the underlying string that was assigned to it before. We’re assigning a whole new string with different content. In this case, it was pretty easy to find the index to change as there are few characters in the string.How are we supposed to know which character to ch...
2. str.index(sub[, start[, end]])index() 方法与 find() 类似，也是查找子字符串 sub 的首次出现位置。但是，当子字符串不存在时，find() 返回 -1，而 index() 则抛出 ValueError 异常。同样支持指定查找范围。s = "Hello, world! This is a test string."# 查找 "world"pos = s.index("world...
但是我们有时候确实需要进行原地修改的时候也可以使用io.StringIO对象或array 模块进行修改 例如: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 >>>importio>>>s="hello, xiaoY">>>sio=io.StringIO(s)>>>sio<_io.StringIO object at0x02F462B0>>>sio.getvalue()'hello, xiaoY'>>>sio.seek(11)...
string = 'All around the world' #Stopatindex3 substring=string[:3] print(substring) # Print"All", 停止索引不包含index(3)位置的字符 Udemy 2022 年完整 Python 开发课程:从零到精通 https://www.koudaizy.com/tutorials/complete-python-developer-zero-to-mastery/ ...
>>> str='string lEARn' >>> str.find('z') #查找字符串,没有则返回-1,有则返回查到到第一个匹配的索引 -1 >>> str.find('n') #返回查到到第一个匹配的索引 4 >>> str.rfind('n') #返回的索引是最后一次匹配的 11 >>> str.index('a') #如果没有匹配则报错 Traceback (most recent...
: count(str, beg=0, end=len(string)) : -- 搜索的子字符串 -- 字符串开始搜索的位置。默认第一个字符,第一个字符索引值为0。 -- 字符串中结束搜索的位置。字符第一个字符的索引为 0。默认字符串的最后一个位置。 值: 该方法返回子字符串在字符串中出现的次数。
The index of the first character of a string is 0. There is no separate character type. A character is simply a string of size 1. Here's how to get the character at a specific index.Python Copy word = 'Python' word[0] # Character in position 0.The output is:...
Return True if the string is an alphabetic string, False otherwise. A string is alphabetic if all characters in the string are alphabetic and there is at least one character in the string. """ pass def isascii(self, *args, **kwargs): # real signature unknown ...