综上所述,当你在Python中看到 'str' object has no attribute 'slice' 的错误时,你应该意识到你正在尝试使用一个不存在的字符串方法。正确的方式是使用索引和切片操作符来实现字符串的切片操作。
x['col2'], axis = 1) 但是,我得到了一个错误:AttributeError: ("'str' object has no attribute 'str'", 'occurred at index 0') col1的数据类型是object: df['col1'].dtypes > dtype('O') 有什么建议吗? 发布于 11 月前 ✅ 最佳回答: 中的lambda分别获取每一行。所以x['col1']是一个st...
end =" ")# a b c# ob1自遍历ob1.__next__()# 报错: 'str' object has no attribute '__next__'# ob2它遍历foriinob2:print(i, end =" ")# a b cforiinob2:print(i, end =" ")# 无输出# ob2自遍历ob2.__next__()# 报错:StopIteration# ob3自遍历ob3.__next__()#...
ob1.__next__() # 报错: 'str' object has no attribute '__next__' # ob2它遍历 for i in ob2: print(i, end = " ") # a b c for i in ob2: print(i, end = " ") # 无输出 # ob2自遍历 ob2.__next__() # 报错:StopIteration # ob3自遍历 ob3.__next__() # a ob3...
ob1.__next__()# 报错:'str'object has no attribute'__next__'# ob2它遍历foriinob2:print(i,end=" ")# a b cforiinob2:print(i,end=" ")# 无输出 # ob2自遍历 ob2.__next__()# 报错:StopIteration # ob3自遍历 ob3.__next__()# a ...
ob1 = "abc"ob2 = iter("abc")ob3 = iter("abc")# ob1它遍历for i in ob1:print(i, end = " ") # a b cfor i in ob1: print(i, end = " ") # a b c# ob1自遍历ob1.__next__() # 报错： 'str' object has no attribute '__next__'# ob2它遍历for i in ...
ob3 =iter("abc")# ob1它遍历foriinob1:print(i, end =" ")# a b cforiinob1:print(i, end =" ")# a b c# ob1自遍历ob1.__next__()# 报错: 'str' object has no attribute '__next__'# ob2它遍历foriinob2:print(i, end =" ")# a b cforiinob2:print(i, end =" ")# ...
30.问:我用字符串方法startwith()测试一个字符串是否以另一个字符串为前缀,怎么会提示“AttributeError: 'str' object has no attribute 'startwith'”这样的错误呢? 答:字符串没有startwith()方法,应该是startswith()。同理,也没有endwith()方法,而是endswith()。
问题：跑代码过程：将int型数据转换为str型数据，出现'str' object has no attribute 'decode'错误。
'''A:处理某一列的空格值''' #'DataFrame' object has no attribute 'str' # 注意DataFrame.str不存在,而Series.str存在 '''处理左空格''' newName = df['name'].str.lstrip() --- Out[18]: 0 KEN 1 JIMI 2 John '''处理右空格''' newName1 = df['name'].str.rstrip() --- Out[23]...