defsqrt_newton(n,epsilon=1e-7):"""使用牛顿迭代法计算平方根:paramn:要计算平方根的数:paramepsilon:迭代精度:return:平方根的近似值"""ifn<0:raiseValueError("Cannot compute square root of a negative number")x=nwhileabs(x*x-n)>epsilon:x=(x+n/x)/2returnx# 使用自定义函数计算平方根root=sq...
在Python标准库`math`模块中,用于计算平方根的函数是`sqrt()`。以下是一个简单的示例: ```python import math #计算平方根 number = 25 square_root = math.sqrt(number) print(f"Square root of {number} is: {square_root}") ``` 在这个例子中,`math.sqrt()`函数被用来计算数字25的平方根。确保在...
array([Decimal('0'), Decimal('0')]) c_res[0] += (c1[0]*c2[0]+c1[1]*c2[1]) / (c2[0]**2+c2[1]**2) c_res[1] += (c1[1]*c2[0]-c1[0]*c2[1]) / (c2[0]**2+c2[1]**2) return c_res def sq(c): # take the square root of a complex number, return a c...
The square root of a number X is a number y such that y*y =X We cannot use this to find the square root of a particular instance of X. Imperative knowledge Here is a "recipe" for deducing a square root of a number X-attributed to Heron of Alexandria in the first century AD 1.S...
square root of a number x is y such that y*y=x recipe for deducing square root of a number x (16) Start with a guess,g If g*g is close enough to x,stop and say g is the answer Otherwise make a new guess by averaging g and x/g Using the new guess,repeat process until clos...
1. math.sqrt()函数只能处理正数,对于负数会返回一个NaN(Not a Number)。 2. 如果需要计算复数的平方根,可以使用cmath模块中的函数。 以上就是Python语言中开根号的函数math.sqrt()的介绍和使用方法。通过该函数,我们可以方便地计算任意数字的平方根。
Case 1: Taking the Square Root of a Negative Number In this case, it’s important to check the number before passing it to themath.sqrt()function. Here’s an example: import math def safe_sqrt(x): if x < 0: raise ValueError("Cannot compute the square root of a negative number") ...
A brief introduction to square roots The ins and outs of the Python square root function,sqrt() A practical application ofsqrt()using a real-world example Knowing how to usesqrt()is only part of the equation. Understanding when to use it is equally important. Now that you know both, go...
importmath# 计算圆的面积radius=5area=math.pi*radius**2print(f"The area of a circle with radius{radius}is{area:.2f}")# 计算平方根number=25sqrt_number=math.sqrt(number)print(f"The square root of{number}is{sqrt_number:.2f}")
message = f"The square root of {x} is {math.sqrt(x):.2f}." print(message) # 输出: The square root of 5 is 2.24. ``` 在这个例子中,`f-string` 不仅嵌入了数学表达式,还调用了函数 `math.sqrt()`,并使用了格式化选项 `.2f` 来控制浮点数的显示精度。