second smallest: Return the second smallest number in a given list These functions seem pretty trivial, and they are. But the trick here is that you need to implement all ofthem recursively. You should also try to be efficient. In particular, no function should ever need to accessany ...
nlargest(2, m) # 最大的2个数对应的,如果用nsmallest则是求最小的数及其索引 max_index = map(m.index, heapq.nlargest(2, m)) print(max_number) # max_index 直接输出来不是数,使用list()或者set()均可输出 print(set(max_index)) 结果: [94, 90] {1, 7} 有重复值的代码: import heapq ...
print(list1 is list2) list3 = list1 print(list3 is list1) 输出 True False True 第一个语句是True,因为list1和list2都持有相同的值,所以它们是相等的。第二个语句为False,因为值指向内存中的不同变量,第三个语句为True,因为list1和list3都指向内存中的公共对象。 15 在一行代码中合并 2 个字典 fir...
print('list01[0] = {}'.format(list01[0])) print('list02[0] = {}'.format(list02[0])) print('list03[-1] = {}'.format(list03[-1])) print('list04[0] = {}'.format(list04[0])) print('list05[0] = {}'.format(list05[0])) print('list05[2][1] = {}'.format(lis...
for num in combinations:resList.append(int("".join(num)))# 步骤3：返回最小值 return min(resList)# 获取数字 number = int(input())# 获取k值，从数字中移除k位数字 k = int(input())# 调用函数，输出结果 print(smallest_number(number, k))3、代码分析：组合（Combinations）是从一组元素中选取...
(二)接收多个输入:按空格划分,用split隔开为list 1.str1 = input('please input nums') numlist = str1 .split(' ') for n in numlist: print(n) 2. a, b, c= map(int, input('please input n,q').split()) #将输入按空格分开后,直接转化为int类型,无需一一转化 ...
foriinlist(perm): print(i) 输出: (1,2,3) (1,3,2) (2,1,3) (2,3,1) (3,1,2) (3,2,1) 它生成 n! 如果输入序列的长度为 n,则排列。 如果想要得到长度为 L 的排列,那么以这种方式实现它。 # A Python program to print all ...
argv 命令行参数list,第一个是程序本身的路径 path 返回模块的搜索路径 modules.keys() 返回已经导入的所有模块的列表 exit(0) 退出程序 a in s or b in s or c in s简写 采用any方式:all() 对于任何可迭代对象为空都会返回True # 方法一 Truein[iins...
# Define a function to find the first missing positive integer in a list def first_missing_number(nums): # Check if the list is empty, return 1 if it is if len(nums) == 0: return 1 # Sort the list in ascending order nums.sort() # Initialize the smallest positive integer as 0 ...
word_counts = Counter(lower_words) #counts the number each time a word appears print word_counts # Counter({'elit': 5, 'sed': 5, 'in': 5, 'adipiscing': 4, 'mollis': 4, 'eu': 3, # 'id': 3, 'nunc': 3, 'consectetur': 3, 'non': 3, 'ipsum': 3, 'nulla': 3, 'pre...