def find_substring_in(s, sub):""" 使用in关键字查找子字符串 """if sub in s:return Trueelse:return False# 定义一个字符串string = 'A New String Hello, World!'sub_string = "Hello"print('例1，源字符串为：', string, ' 待查找字符串为：', sub_string)print('子字符串是否包含：...
引发 ValueErrortry: pos = s.index("notfound")except ValueError as e: print(e) # 输出：'notfound' is not in string# 查找 "string"，限定在索引 0 到 10 之间try: pos = s.index("string", 0, 10)except ValueError as e: print(e) # 输出：'string' is not in range(...
'我来到北京清华大学'] for string in strings: result = jieba.cut(string, cut_all=False) ...
if any(substring in my_str for substring in my_list): # 👇️ this runs print('The string contains at least one element from the list') else: print('The string does NOT contain any of the elements in the list') 1. 2. 3. 4. 5. 6. 7. 8. 9. 如果需要检查列表中的任何元素...
search_string=input("请输入需要判断的字符串:") 1. 这里我们使用input函数来获取用户输入的字符串,并将其赋值给search_string变量。 步骤3:使用for循环遍历列表 现在,我们使用for循环遍历列表中的每个字符串。可以使用以下代码实现: forstringinlist_of_strings: ...
.join(x.capitalize() for x in s.split(sep)) 57 58 59 # Construct a translation string 60 _idmapL = None 61 def maketrans(fromstr, tostr): 62 """maketrans(frm, to) -> string 63 64 Return a translation table (a string of 256 bytes long) 65 suitable for use in string.translate...
| Return a copy of the string S with leading whitespace removed. | If chars is given and not None, remove characters in chars instead. | | partition(...) | S.partition(sep) -> (head, sep, tail) | | Search for the separator sep in S, and return the part before it, ...
string="The quick brown fox" # 获取最后两个字符 substring1 =string[-2:] print(substring1) # Prints"ox" # 舍弃最后三个字符 substring2 =string[:-3] print(substring2) # Print"The quick brown " 获取字符串中的一个字符 这个很简单,如果切片中没有:字符,只包含数字,它将返回该索引处的字符。
如果不是起始位置 函数语法： re.match(pattern,string,flags=0) re.search函数#search：re.search扫描...