Write a Python function to round up a number to specified digits. Sample Solution: Python Code: importmathdefroundup(a,digits=0):n=10**-digitsreturnround(math.ceil(a/n)*n,digits)x=123.01247print("Original Number: ",x)print(roundup(x,0))print(roundup(x,1))print(roundup(x,2))print(r...
Python uses the math module, NumPy, and Pandas libraries to offer different methods of rounding up numbers. Round up using the math module The math.ceil() function from math is used to round up a number to the nearest integer. The syntax is shown below. # Import the math module to acce...
Int( number )将数字向下舍入到最接近的整数,例: 与期相反,CEILING函数是向上取整 CEILING(number, significance),ceiling英文是天花板的意思,函如其名,返回将参数number 向上舍入(沿绝对值增大的方向)为最接近的指定基数的倍数 不论参数 number 的符号如何,数值都是沿绝对值增大的方向向上舍入,这里和ROUNDUP一样 ...
round单词本身有四舍五入的意思,up则是向上,表示向上取位, ROUNDUP(number, num_digits) 第一个参数是数值, 第二个是向上取舍的位数,取整数 如果num_digits 大于 0(零),则将数字向上舍入到指定的小数位数。 如果num_digits 为 0,则将数字向上舍入到最接近的整数。 如果num_digits 小于 0,则将数字向上舍...
A. round() 函数 使用方法：round(number, digits)描述：round() 函数是Python中最简单直接的方法之一，用于四舍五入数字到指定的小数位数。它接受两个参数：要四舍五入的数字和小数位数（本例中为2）。示例：rounded_number = round(3.14159, 2)print(rounded_number) # 输出: 3.14 B. 字符串格式化 使...
In the above examples, it looks as if decimal.ROUND_05UP rounds everything toward zero. In fact, this is exactly how decimal.ROUND_05UP works, unless the result of rounding ends in a 0 or 5. In that case, the number gets rounded away from zero:...
Round upwards towards infinity: 0.05883 Round down towards negative infinity: 0.05882 Flowchart: For more Practice: Solve these Related Problems: Write a Python program to round a given Decimal number upward (ceil) and downward (floor) with precision 4, and then print both results. ...
Evenly round to the given number of decimals. 翻译就是:a表示需要保留小数位数的数组或数字,decimals表示要保留的小数位数 In [138]: np.around(3.124, 2) Out[138]: 3.12 In [139]: np.around(3.125, 2) Out[139]: 3.12 In [140]: np.around(3.126, 2) ...
>>> round(1.248,2) 1.25 >>> round(1.241,2) 1.24 >>> round(-1.248,1) -1.2 >>> round(1.25,1) 1.2 >>> 这里注意:round(4.5)的结果是4,round(4.51)的结果才是5,这里要看5后面的数字,只有大于5时才进1,恰好等于5时还是舍去的。这与我们字面上理解的”五入“有所出入(Python 3.7.4)。
def round(number, ndigits=None): """强制四舍五入""" exp = Decimal('1.{}'.format(ndigits * '0')) if ndigits else Decimal('1') return type(number)(Decimal(number).quantize(exp, ROUND_HALF_UP)) print(round(4.115, 2), type(round(4.115, 2))) ...