defis_palindrome(string): reversed_string=#???returnstring ==reversed_string>>> is_palindrome('TACOCAT') True>>> is_palindrome('TURBO') False 显然,我们需要弄清楚如何反转字符串以is_palindrome在Python中实现此功能应该怎么做? Python的str字符串对象没有内置.reverse()方法,就像其他语言(例如Java或C#)...
defis_palindrome(string):reversed_string=#???returnstring==reversed_string>>>is_palindrome('TACOCAT')True>>>is_palindrome('TURBO')False 显然,我们需要弄清楚如何反转字符串以is_palindrome在Python中实现此功能应该怎么做? Python的str字符串对象没有内置.reverse()方法,就像其他语言(例如Java或C#)进入Python...
def reverse_string(s): """ 返回逆序的字符串 """ if len(s) == 0: # 基线条件 return s else: # 递归条件 return reverse_string(s[1:]) + s[0] print(reverse_string("Hello")) # 输出: "olleH" 计算幂 def power(base, exp): """ 返回base的exp次幂 """ if exp == 0: # 基线...
Below is the algorithm (steps) to find whether given string is Palindrome or not in Python:First, find the reverse string Compare whether revers string is equal to the actual string If both are the same, then the string is a palindrome, otherwise, the string is not a palindrome....
reverse_str = test[::-1] print("Reverse String: ", reverse_str) Output: String: Python Programming First Character: P Last Character: g Except First Char.: ython Programming Except First Char.: Python Programmin Between two character: thon Programmi ...
print(reverse_string("Hello"))# 输出: "olleH" 计算幂 defpower(base, exp): """ 返回base的exp次幂 """ ifexp ==0:# 基线条件 return1 else:# 递归条件 returnbase * power(base, exp-1) print(power(2,3))# 输出: 8 判断字符串是否为回文 ...
1# Reversing a string using slicing 2 3my_string = "ABCDE" 4reversed_string = my_string[::-1] 5 6print(reversed_string) 7 8# Output 9# EDCBA 在这篇文章(https:///swlh/how-to-reverse-a-string-in-python-66fc4bbc7379)中,你可以了解更多细节。
s.reverse() 1. 2. 3. 解法二(前后对称交换): class Solution: def reverseString(self, s: List[str]) -> None: total = int(len(s)) count = int(total/2) for i in range(count): tmep = s[i] s[i] = s[total-1-i] s[total-1-i] = tmep ...
def is_palindrome(s):reverse = s[::-1]if (s == reverse):return Truereturn False s1 = 'racecar's2 = 'hippopotamus' print('\'racecar\' a palindrome -> {}'.format(is_palindrome(s1)))print('\'hippopotamus\' a palindrome -> ...
test_string='Python Programming'string_reversed=test_string[-1::-1]print(string_reversed)string_reversed=test_string[::-1]print(string_reversed)# String reverse logically defstring_reverse(text):r_text=''index=len(text)-1whileindex>=0:r_text+=text[index]index-=1returnr_textprint(string_re...