defis_palindrome(string): reversed_string=#???returnstring ==reversed_string>>> is_palindrome('TACOCAT') True>>> is_palindrome('TURBO') False 显然,我们需要弄清楚如何反转字符串以is_palindrome在Python中实现此功能应该怎么做? Python的st
defis_palindrome(string):reversed_string=#???returnstring==reversed_string>>>is_palindrome('TACOCAT')True>>>is_palindrome('TURBO')False 显然,我们需要弄清楚如何反转字符串以is_palindrome在Python中实现此功能应该怎么做? Python的str字符串对象没有内置.reverse()方法,就像其他语言(例如Java或C#)进入Python...
def reverse_string(s): """ 返回逆序的字符串 """ if len(s) == 0: # 基线条件 return s else: # 递归条件 return reverse_string(s[1:]) + s[0] print(reverse_string("Hello")) # 输出: "olleH" 计算幂 def power(base, exp): """ 返回base的exp次幂 """ if exp == 0: # 基线...
1my_string = "abcba"23if my_string == my_string[::-1]:4 print("palindrome")5else:6 print("not palindrome")78# Output9# palindrome 元素重复次数 在Python中,有很多方法可以做这件事情,但是我最喜欢的还是 Counter 这个类。 Counter会计算每一个元素出现的次数,Counter()会返回一个字典,元...
1# Reversing a string using slicing 2 3my_string = "ABCDE" 4reversed_string = my_string[::-1] 5 6print(reversed_string) 7 8# Output 9# EDCBA 在这篇文章(https:///swlh/how-to-reverse-a-string-in-python-66fc4bbc7379)中,你可以了解更多细节。
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s.reverse() 1. 2. 3. 解法二(前后对称交换): class Solution: def reverseString(self, s: List[str]) -> None: total = int(len(s)) count = int(total/2) for i in range(count): tmep = s[i] s[i] = s[total-1-i] s[total-1-i] = tmep ...
palindrome or not my_str = 'aIbohPhoBiA' # make it suitable for caseless comparison my_str = my_str.casefold() # reverse the string rev_str = reversed(my_str) # check if the string is equal to its reverse if list(my_str) == list(rev_str): print("The string is a palindrome....
def is_palindrome(s):reverse = s[::-1]if (s == reverse):return Truereturn False s1 = 'racecar's2 = 'hippopotamus' print('\'racecar\' a palindrome -> {}'.format(is_palindrome(s1)))print('\'hippopotamus\' a palindrome -> ...
属于回文数，所以is_palindrome函数返回True；而num2的数值为12345，不是回文数，所以is_palindrome函数返回False。需要注意的是，以上代码只能判断整数是否为回文数。如果需要判断字符串是否为回文，可略作修改，如下代码所示：```python def is_palindrome(string):reverse_str = string[::-1] # 将字符串逆序 ...