file-like Object:像open()函数返回的这种有个read()方法的对象,在Python中统称为file-like Object。除了file外,还可以是内存的字节流,网络流,自定义流等等。file-like Object不要求从特定类继承,只要写个read()方法就行。 StringIO就是在内存中创建的file-like Object,常用作临时缓冲。 • 写文件 调用open( ...
``` # Python script to rename multiple files in a directory import os def rename_files(directory_path, old_name, new_name): for filename in os.listdir(directory_path): if old_name in filename: new_filename = filename.replace(old_name, new_name) os.rename(os.path.join(directory_path...
rename(path, path2) print("old = %s" % path) print("new = %s" % path) i+=1 #注意这里的i是一个陷阱 #或者 #img_ext = 'bmp|jpeg|gif|psd|png|jpg' #if file_ext in img_ext: # print('ok---'+file_ext) elif os.path.isdir(path): for x in os.listdir(path): change_name...
执行/path/to/directory/__main__.py中的代码。 运行python /path/to/filename.zip时,Python 会把文件当做一个目录。 换句话说,Python 会做以下两件事: 将【目录】添加到模块路径中。 执行从/path/to/filename.zip中提取的__main__.py中的代码。 Zip 是一种面向端的格式:元数据和指向数据的指针都在末尾。
Theos.rename()method raises the FileExistsError or OSError when the destination file name already exists. This can be avoided by wrapping our code in thetry-exceptblock. Use theisfile(‘path’)function before renaming a file. It returns true if the destination file name already exists. ...
() 删除一个文件11os.rename("oldname","new") 重命名文件/目录12os.stat('path/filename') 获取文件/目录信息13os.sep 操作系统特定的路径分隔符,win下为"\\",Linux下为"/"14os.linesep 当前平台使用的行终止符,win下为"\t\n",Linux下为"\n"15os.pathsep 用于分割文件路径的字符串16os.name ...
a directoryimport osdef rename_files(directory_path, old_name, new_name):for filename in os.listdir(directory_path):if old_name in filename:new_filename = filename.replace(old_name, new_name)os.rename(os.path.join(directory...
In order to rename a file, the first thing we need is the path of the file. The path is the location of the file on the disk in a computer system. To be more particular, an Absolute path contains the complete directory list required to locate the file and a Relative path contains th...
import os os.mknod('file.txt') 1. 2. 删除文件 import os os.remove('file.txt') 1. 2. 2.8 重命名 import os os.rename('date.txt','file.txt') 1. 2. 2.9 判断文件/目录是否存在 import os from os.path import exists print(os.path.exists('file.txt')) print(os.path.exists('file1...
(output_folder, zip_name) os.rename(new_xlsx_file_path, new_zip_file_path) extract_folder = os.path.join(output_folder, 'files') with zipfile.ZipFile(new_zip_file_path, 'r') as f: for files in f.namelist(): f.extract(files, extract_folder) os.remove(new_zip_file_path) media...