>>>lst=[1,2,3]>>>lst.remove(4)Traceback(most recent call last):File"<stdin>",line1,in<module>ValueError:list.remove(x):xnotinlist pop L.pop(index) -> item -- remove and return item at index (default last). Raises IndexError if list is empty or index is out of range. pop...
L.pop([index]) -> item – remove and return item at index (default last). Raises IndexError if list is empty or index is out of range. pop是删除指定索引位置的元素,参数是 index。如果不指定索引,默认删除列表最后一个元素。 >>>lst=[1,2,3]>>>lst.pop(1)2>>>lst[1,3]>>>lst=[1,...
需要注意,remove方法没有返回值,而且如果删除的元素不在列表中的话,会发生报错。 >>>lst=[1,2,3]>>>lst.remove(4)Traceback(mostrecentcalllast):File"<stdin>",line1,in<module>ValueError:list.remove(x):xnotinlist pop L.pop([index]) -> item -- remove and return item at index (default la...
File "<stdin>", line 1, in <module> ValueError: list.remove(x): x not in list pop L.pop([index]) -> item — remove and return item at index (default last). Raises IndexError if list is empty or index is out of range. pop是删除指定索引位置的元素,参数是 index。如果不指定索引,...
Remove and return item at index (default last). Raises IndexError if list is empty or index is out of range. """ pass 翻译:默认移除对象的最后一个值 如果列表为空或者索引超出范围,则抛出IndexError View Code 9.remove def remove(self, *args, **kwargs): # real signature unknown ...
|insert(...)| L.insert(index, object) --insert object before index| |pop(...)| L.pop([index]) -> item -- removeandreturnitem at index (default last).| Raises IndexErroriflistisemptyorindexisout of range.| |remove(...)| L.remove(value) -> None --remove first occurrence of ...
.__delitem__()list说到方法，Python 列表有.remove()和.pop()方法，它们分别允许您按值或索引删除项目：>>> pets = ["dog", "cat", "fish", "bird", "hamster"]>>> pets.remove("fish") # Equivalent to del pets[2]>>> pets['dog', 'cat', 'bird', 'hamster']>>> pets.pop(3)'...
在Python中使用os.remove()删除文件夹 您可以尝试使用shutil模块: import shutilN=[1,3]for i in N: shutil.rmtree(rf"C:\Users\User\Test1\{i}") 无法使用python中的os.remove()从文件夹中删除文件 您需要为要删除的文件指定目录。我将创建一个变量来保存文件路径的字符串,如下所示: directory = 'source...
# Access a single item of Python List a = [52, 85, 41, 'sum', 'str', 3 + 5j, 6.8] # access 3rd item with index 2 x = a[2] print(x) print(type(x)) 1. 2. 3. 4. 5. 6. 执行和输出: 2.2. 访问 Python 列表中的多个项 ...
Theremove()function will return a value error if an item is not in the list. Therefore, it is important to add an exception to handle such scenarios. The code below shows an example of catching the error for items not in the list. ...