Remove the first item from the list whose value isx. It is an error if there is no such item. list.pop([i]) 删除list中指定索引位置的元素,如果不加索引【list.pop()】,则删除的是最后一个元素 Remove the item at the given position in the
list.remove(x)#删除 list 中第一个值为 x 的元素(即如果 list 中有两个 x , 只会删除第一个 x ) Remove the first item from the list whose value isx. It is an error if there is no such item. list.pop([i])#删除 list 中的第 i 个元素并且返回这个元素。如果不给参数 i ,将默认删除...
list.remove(x)Remove the first item from the list whose value is equal to x. It raises a ValueError if there is no such item.从列表中移出值为x的第一个对象。如果找不到相应的对象会提供一个错误代码ValueError。list.pop([i])Remove the item at the given position in the list, and return ...
Method-4: Remove the first element of the Python list using the remove() method Theremove()method in Python removes the first occurrence of a specified value from a list. However, we must know the actual value that we want to remove, not just its position. If we want to remove the fi...
L.pop(index) -> item -- remove and return item at index (default last). Raises IndexError if list is empty or index is out of range. pop是删除指定索引位置的元素,参数是 index。如果不指定索引,默认删除列表最后一个元素。 代码语言:python ...
Below is a basic example of using theremove()function. The function will remove the item with the value3from the list. Theremove()function will only remove the first occurrence of an item in a list if there are duplicates in the same list. In the following example, theremove()function ...
# Remove the first dog from the list. del dogs[0] print(dogs) 通过值移除元素 remove()函数可以通过元素的值来移除元素。给定元素值和要删除的列表名,Python 会搜索给定列表,直到找到第一个和给定值相同的元素,然后移除元素。代码示例如下: dogs = ['border collie', 'australian cattle dog', 'labrador...
print(third_item) # item3 print(rest) # ['item4', 'item5'] # First Example fruits = ['banana', 'orange', 'mango', 'lemon','lime','apple']first_fruit, second_fruit, third_fruit, *rest = lstprint(first_fruit) # banana
first_student = students[0] # "Alice" last_student = students[-1] # "Charlie"2.1.1.2 列表的增删改操作 列表提供了丰富的内置方法来改变其内容: •增:append()、extend()、insert() •删:remove()、pop()、del关键字、clear() •改:直接赋值或使用list[index] = new_value ...
print list[2]; 1. 2. 3. 4. 5. 6. 7. 8. 以上实例的输出结果是: Value available at index 2 : 1997 New value available at index 2 : 2001 使用append()方法来添加列表项 >>> s=['physics','chemistry'] >>> s.append("wangtao") ...