def remove_duplicates(input_list): seen = set() unique_list = [] duplicates = [] for item in input_list: if item not in seen: unique_list.append(item) seen.add(item) else: duplicates.append(item) return unique_list, duplicates 示例 my_list = [ 1, 2, 3, 1, 2, 3, 4, 5]...
# initializing listtest_list = [1,3,5,6,3,5,6,1]print("The original list is : "+ str(test_list)) # using naive method to remove duplicated from listres = []foriintest_list:ifinotinres:res.append(i) # printing list after ...
def remove_duplicates_with_loop(input_list): output_list = [] for item in input_list: if item not in output_list: output_list.append(item) return output_list 示例 input_list = [1, 2, 2, 3, 4, 4, 5] output_list = remove_duplicates_with_loop(input_list) print(output_list) 在...
# using list comprehension# to remove duplicated # from list res = [][res.append(x) for x in test_list if x not in res] # printing list after removal print ("The list after removing duplicates : " + str(res)) → 输出结果: The ...
But dictionaries are also iterables (looping over a dictionary provides the keys), so we could simply pass the dictionary to the built-in list constructor:>>> unique_colors = list(dict.fromkeys(all_colors)) >>> unique_colors ['blue', 'purple', 'green', 'red', 'pink'] ...
from functools import reduce def remove_duplicates(lst): return reduce(lambda x, y: x + [y] if y not in x else x, lst, []) # 示例 lst = [{'a': 1, 'b': 2}, {'b': 2, 'a': 1}, {'c': 3}] print(remove_duplicates(lst)) 方法三:使用 pandas 库 如果列表中的字典数量...
在Python中,剔除列表(list)中的重复元素是一个常见的任务。以下是几种实现方法,每种方法都利用了Python中不同的数据结构和特性: 使用集合(set): 集合是一个无序的不重复元素集。通过将列表转换为集合,可以自动去除重复元素,然后再将集合转换回列表。 python def remove_duplicates_using_set(one_list): return ...
new_list = remove_duplicates(my_list)print(new_list) 代码解析: 首先定义了一个名为remove_duplicates的函数,该函数接受一个列表作为参数,并返回一个去重后的新列表new_lst。 在循环中,我们逐个遍历原始列表中的元素。 使用in关键字检查该元素是否已经存在于新列表new_lst中,如果不存在则将其添加到new_lst中...
# using list comprehension # to remove duplicated # from list res = [][res.append(x) for x in test_list if x not in res]# printing list after removal print ("The list after removing duplicates : " + str(res))→输出结果：The original list is : [1, 3, 5, 6, 3, 5, 6, 1]...
return list(set(original_list)) 使用列表推导式 def remove_duplicates_list_comprehension(original_list): unique_list = [] [unique_list.append(item) for item in original_list if item not in unique_list] return unique_list 使用字典 def remove_duplicates_dict(original_list): ...