L.remove(value) -> None -- remove first occurrence of value. Raises ValueError if the value is not present. remove是从列表中删除指定的元素,参数是 value。 举个例子: 代码语言:python 代码运行次数:0 运行 AI代码解释 >>>lst=[1,2,3]>>>lst.remove(2)>>>lst[1,3] 需要注意,remove方法没有...
| L.clear() -> None -- remove all items from L | | copy(...) | L.copy() -> list -- a shallow copy of L | | count(...) | L.count(value) -> integer -- return number of occurrences of value | | extend(...) | L.extend(iterable) -> None -- extend list by appendin...
Theremove()method takes a single element as an argument and removes it from the list. If theelementdoesn't exist, it throwsValueError: list.remove(x): x not in listexception. Return Value from remove() Theremove()doesn't return any value (returnsNone). Example 1: Remove element from th...
#创建列表list() ->new empty list#追加列表|append(...)| L.append(object) -> None --append object to end#清除列表|clear(...)| L.clear() -> None -- remove all itemsfromL#复制...|copy(...)| L.copy() -> list --a shallow copy of L#计数|count(...)| L.count(value) ->...
Remove all items from the list. Equivalent to del a[:].移除列表中所有的对象。等效于del a[:]。list.index(x[, start[, end]])Return zero-based index in the list of the first item whose value is equal to x. Raises a ValueError if there is no such item.在等于 x 的第一个项中返回...
print(list) [1, 2, 3, 4, 'a'] #显示结果 1. 2. 3. 4. 5. insert 4. pop 描述:删除队列中最后一个对象 语法: def pop(self, index=None): # real signature unknown; restored from __doc__ """ L.pop([index]) -> item -- remove and return item at index (default last). ...
print("删除第三个元素 : ",list) 以上实例输出结果: 原始列表:['Google','Runoob',1997,2000]删除第三个元素:['Google','Runoob',2000] 注意:我们会在接下来的章节讨论 remove() 方法的使用 Python列表脚本操作符 列表对 + 和 * 的操作符与字符串相似。+ 号用于组合列表,* 号用于重复列表。
) | L.clear() -> None -- remove all items from L | | copy(...) | L.copy() -> list -- a shallow copy of L | | count(...) | L.count(value) -> integer -- return number of occurrences of value | | extend(...) | L.extend(iterable) -> None -- extend list by ...
) S.split([sep [,maxsplit]]) -> list of strings #sep为分隔符,默认为空格 最大分隔次数 Return a list of the words in the string S, using sep as the delimiter string. If maxsplit is given, at most maxsplit splits are done. If sep is not specified or is None, any whitespace ...
async def wait(fs, *, loop=None, timeout=None, return_when=ALL_COMPLETED): if futures.isfuture(fs) or coroutines.iscoroutine(fs): raise TypeError(f"expect a list of futures, not {type(fs).__name__}") if not fs: raise ValueError('Set of coroutines/Futures is empty.') if return...