来吧,调整一下python代码。 importreregex=r'Router ID: (\S+) +Address: (\S+).+?Neighbor is up for (\S+)'withopen('ospf_peer.txt')asf:ospf_peer=f.read()match=re.finditer(regex,ospf_peer,re.DOTALL)forminmatch:print(m.groups()) 强调一下的是.+禁用贪婪模式的方法是在其后面打上?问...
\s -- (lowercase s) matches a single whitespace character -- space, newline, return, tab, form [ \n\r\t\f]. \S (upper case S) matches any non-whitespace character. \t, \n, \r -- tab, newline, return \d -- decimal digit [0-9] (some older regex utilities do not support...
\s Matches any whitespace character; equivalent to [ \t\n\r\f\v] in bytes patterns or string patterns with the ASCII flag. In string patterns without the ASCII flag, it will match the whole range of Unicode whitespace characters. \S Matches any non-whitespace character; equivalent to [^\...
\ Escape special char or start a sequence. . Match any char except newline, see re.DOTALL ^ Match start of the string, see re.MULTILINE $ Match end of the string, see re.MULTILINE [] Enclose a set of matchable chars R|S Match either regex R or regex S. () Create capture group...
\sReturns a match where the string contains a white space character"\s"Try it » \SReturns a match where the string DOES NOT contain a white space character"\S"Try it » \wReturns a match where the string contains any word characters (characters from a to Z, digits from 0-9, an...
2.2 re.match() 除了serch,我们还可以使用match(regex, email)方法,比较regex和我们的目标字符串。 importreemail='brycewang123@gmail.com'pattern=r"^[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[...
\$a match if a string contains $ followed by a. Here, $ is not interpreted by a RegEx engine in a special way.If you are unsure if a character has special meaning or not, you can put \ in front of it. This makes sure the character is not treated in a special way....
Regex匹配在regex测试器上工作,但在oracle中不起作用。 、、 我有regex \bname[^a-zA-Z]+[0-9]+。此正则表达式适用于,但不适用于甲骨文。我想要的模式是:<exact word "name" (upper or lower case)><any character/s that is a non-alphabet (including line breaks) or it can be no charact...
match("dog", 1) # Match as "o" is the 2nd character of "dog". <re.Match object; span=(1, 2), match='o'> 如果你想定位匹配在 string 中的位置,使用 search() 来替代(另参考 search() vs. match())。 Pattern.fullmatch(string[, pos[, endpos]]) 如果整个 string 匹配这个正则表达式...
In the first example, the regex 1.3 matches '123' because the '1' and '3' match literally, and the . matches the '2'. Here, you’re essentially asking, “Does s contain a '1', then any character (except a newline), then a '3'?” The answer is yes for 'foo123bar' but no...