Python程序LeapYear源码 import math def valid(month,day,year):if day>31:return False elif month==2:if leap(year):if day <=29:return True else:return False else:if day<=28:return True else:return False elif month==4 or 6 or 9 or 11:if day>31:return False else:return True else:r...
and it presents them in order too. All we need to do is take the written prompt and translate it into code. First, using themodulooperator, we check to make sure the year can evenly be divided by 4. If itcan’t, we keep ‘False’ as the value for our leap variable and return...
下面是一个Python判断闰年的代码示例: def is_leap_year(year): if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0): return True else: return False year = int(input("请输入一个年份:")) if is_leap_year(year): print(f"{year}年是闰年") else: print(f"{year}年不...
6.程序实现的功能:输入某年某月某日,判断这一天是这一年的第几天,Python代码如下def leap(year):leap=0if(year%400==0)or((year%4==0)and(year%100!=0)leap=1①y=int(input("请输入年份:"))m=int(input("请输人月份:"))d=int(input("请输入日:"))months=(0,31,59,90,120,151,181,212,...
Python Leap Year #The test case is passing 4/6. I don't know what is wrong with my code, please help year = int(input()) if year % 4 == 0: if year % 100 == 0: if year % 400 == 0: print("Leap year") else: print("Not a leap year") else: print("Not a leap year...
if is_leap(year): print("您输入的年份是闰年。") else: print("您输入的年份不是闰年。") 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 2、定义一个count_str_char(my_str)函数,该函数返回参数字符串中包含多少个数字,多少个字母,多少个空白字符,多少...
= 0 instead of == 0 to output a print command. Here's what I came up with. I didn't see that step 2 said "IS a leap year" which stumped me for a while. year = int(input()) #your code goes here if year % 4 != 0: print("Not a leap year") elif year % 100 != 0:...
for year in range(birth_year, current_time.tm_year + 1): # 根据年份判断是否为闰年,并累加相应的天数 total_days += 366 if is_leap_year(year) else 365 # 计算从出生年份到当前月份的所有额外天数 for month in range(1, current_time.tm_mon): ...
经典题目:输入年份判断闰年 year = int(input('请输入年份')) leap_year = year % 4 == 0 && year % 100 != 0 || year % 400 == 0 print(leap_year) 输入:2000 结果:True 三、分支结构 在python中分支结构使用if-elif-else 代码语言:javascript 复制 题目:百分制成绩转换为等级制成绩如果输入...
Python Program to Check Leap Year To understand this example, you should have the knowledge of the following Python programming topics: Python Operators Python if...else Statement A leap year is exactly divisible by 4 except for century years (years ending with 00). The century year is a lea...