# Python program to check if the input number is odd or even. # A number is even if division by 2 gives a remainder of 0. # If the remainder is 1, it is an odd number. num = int(input("Enter a number: ")) if (num % 2) == 0: print("{0} is Even".format(num)) else...
Python program to create a function to check EVEN or ODD # Python function to check EVEN or ODDdefCheckEvenOdd(num):if(num%2==0):print(num," is EVEN")else:print(num," is ODD")# main codeCheckEvenOdd(11)CheckEvenOdd(22)CheckEvenOdd(33)CheckEvenOdd(44) ...
Write a Python program that determines whether a given number (accepted from the user) is even or odd, and prints an appropriate message to the user. Pictorial Presentation of Even Numbers: Pictorial Presentation of Odd Numbers: Sample Solution: Python Code: # Prompt the user to enter a numbe...
Here, we will learn how to create two lists with EVEN and ODD numbers from a given list in Python? To implement this program, we will check EVEN and ODD numbers and appends two them separate lists.ByIncludeHelpLast updated : June 22, 2023 ...
你不需要对每一行都检查一次odd_even的值；只需要检查一次，就能确定count %2应该和什么进行比较。你...
ReadPython Hello World Program Method 2. Use Bitwise AND Operator (&) Another efficient way to check for odd or even numbers in Python is by using the bitwise AND operator (&). This method relies on the fact that the least significant bit of an even number is always 0, while it’s ...
print('The value of pi is approximately', math.pi) The value of piisapproximately3.141592653589793 注意,print函数会在值之间添加空格。 2.7. 参数 当你调用一个函数时,括号中的表达式被称为参数。通常我会解释为什么,但是在这种情况下,术语的技术含义几乎与词汇的常见含义无关,所以我就不尝试了。
even_or_odd.py number = input("Enter a number, and I'll tell you if it's even or odd: ") number = int(number) if number % 2 == 0: print("\nThe number " + str(number) + " is even.") else: print("\nThe number " + str(number) + " is odd.") ...
prompt += "\nEnter 'quit' to end the program. " 02、使用int()函数 (1)input输入的值默认为字符串型,如果时输入的是数字,并且后面的程序需要用到这个数字,则用int()函数,将输入的数字从字符串型转换成整数型,如下: num = input("Enter a num,and I'll tell you if it's even or odd: ") ...
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