# python program to find floor divisiona=10b=3# finding divisionresult1=a/bprint("a/b = ",result1)# finding floor divisionresult2=a//bprint("a/b = ",result2) Output a/b = 3.3333333333333335 a/b = 3 Advertisement Advertisement
那个类也有相关的方法,比如findArea或者findPerimeter。shape类有子类,更具体。正方形是一个shape对象,其值shapeType等于square,numberOfSides等于4。它的findArea方法获取lengthOfSides值并求平方。同时,triangle对象对于name、shapeType、numberOfSides有不同的值,其findArea方法也不同。这个例子在快速介绍对象的同时,也...
To find the square of a number - simple multiple the number two times.Example# Python program to calculate square of a number # Method 1 (using number*number) # input a number number = int (raw_input ("Enter an integer number: ")) # calculate square square = number*number # print ...
Unit Digit of a raised to power b.py Untitled.ipynb Voice Command Calculator.py WeatherGUI.py Web Socket.py Web_Scraper.py WikipediaModule.py add_two_number.py add_two_nums.py advanced_calculator.py agecalculator.py alexa_news_headlines.py area_of_square_app.py armstrong...
1#A program to calculate the cost per square inch of2#a circular pizze, given its diameter and price3importmath4defmain():5diameter = float(input("diameter(in inches):"))6price = float(input("price (in cents):"))7area = math.pi * (diameter / 2) ** 28cost = price /area9print...
print("volume: {0}\nsurface area: {1}".format(volume, area)) main() 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 2.给定圆形比萨饼的直径和价格,编写一个程序,计算每平方英寸的成本。面积公式为 。 # A program to calculate the cost per square inch of ...
The square root of a number X is a number y such that y*y =X We cannot use this to find the square root of a particular instance of X. Imperative knowledge Here is a "recipe" for deducing a square root of a number X-attributed to Heron of Alexandria in the first century AD ...
defconnect_to_next_port(self,minimum):"""Connects to the next available port.Args:minimum:Aport value greater or equal to1024.Returns:Thenewminimumport.""" assert minimum>=1024,'Minimum port must be at least 1024.'port=self._find_next_open_port(minimum)assert port is not Nonereturnport ...
To use: >>> sq = Square(3) >>> sq.area 9 >>> sq.perimeter 12 >>> sq.area = 16 >>> sq.side 4 >>> sq.perimeter 16 """ def __init__(self, side): self.side = side @property def area(self): """Area of the square.""" return self._get_area() @area.setter def ar...
square root of a number x is y such that y*y=x recipe for deducing square root of a number x (16) Start with a guess,g If g*g is close enough to x,stop and say g is the answer Otherwise make a new guess by averaging g and x/g Using the new guess,repeat process until clos...