Python program to check leap year by using the calendar module # importing the moduleimportcalendar# input the yearyear=int(input('Enter the value of year: '))leap_year=calendar.isleap(year)# checking leap yearifleap_year:# to check conditionprint('The given year is a leap year.')else:...
The output of Leap Year Program In Python: 2024 is a leap year. Also Read: How to check for Armstrong Number in Python? Different Methods to Find Leap Year In Python Programming There are a lot of different methods to find the leap year in the Python Program. Here are a few: i) ...
defis_leap(year):# variable to check the leap yearleap =False# divided by 100 means century year# century year divided by 400 is leap yearif(year %400==0)and(year %100==0):# change leap to Trueleap =True# not divided by 100 means not a century year# year divided by 4 is a ...
In this tutorial, we’ll write a leap year program inpythonto check whether the input year is a leap year or not. Before we enterPythonleap year programs, Let’s see the Python Leap Year’s definition and logic. How to Calculate Leap Year Python Program to Check Leap Year How to Calcu...
6.程序实现的功能:输人某年某月某日,判断这一天是这一年的第几天,Python代码如下: d e f leap(year):$$ l e a p = 0 $$$ i f ( y e a r \% 4 0 0 = = 0 ) o r ( ( y e a r \% 4 = = 0 ) a n d ( y e a r \% 1 0 0 ! = 0 ) ) : $$$ l e a ...
Determine Leap Year Through a Simpleif-elseConstruct in Python The following implementation uses a simpleif-elseconstruct to determine a leap year. For a given year input, we first check if the second condition is satisfied; if so, we show our positive judgment (i.e., the year is a leap...
Checking date is valid or not in Python: In this tutorial, we will learn how to check a given date is valid or not in the Python programming language?ByBipin KumarLast updated : January 04, 2024 Problem statement Write a Python program to input a date, and check whether it is valid or...
Python程序LeapYear源码 import math def valid(month,day,year):if day>31:return False elif month==2:if leap(year):if day <=29:return True else:return False else:if day<=28:return True else:return False elif month==4 or 6 or 9 or 11:if day>31:return False else:return True else:r...
python求闰年代码并打印列表 python求闰年个数,1、定义一个is_leap(year)函数,该函数可以判度year是否为闰年。若是闰年,则返回True;否则返回False。importsysdefis_leap(year):year=int(year)ifyear%4!=0:returnFalseelifyear%100!=0:returnTru
Log inRegister 0 Python Leap Year #The test case is passing 4/6. I don't know what is wrong with my code, please help year = int(input()) if year % 4 == 0: if year % 100 == 0: if year % 400 == 0: print("Leap year") else: print("Not a leap year") else: print(...