# Python program to check prime number# Function to check prime numberdefisPrime(n):returnall([(n%j)forjinrange(2,int(n/2)+1)])andn>1# Main codenum=59ifisPrime(num):print(num,"is a prime number")else:print(num,"is not a prime number")num=7ifisPrime(num):print(num,"is a ...
# Program to check if a string is palindrome or not my_str = 'aIbohPhoBiA' # make it suitable for caseless comparison my_str = my_str.casefold() # reverse the string rev_str = reversed(my_str) # check if the string is equal to its reverse if list(my_str) == list(rev_str):...
# Python program to check if a string is # palindrome or not # function to check palindrome string def isPalindrome(string): rev_string = string[::-1] return string == rev_string # Main code x = "Google" if isPalindrome(x): print(x,"is a palindrome string") else: print(x,"is...
Here is source code of the Python Program to check whether a string is a palindrome or not using recursion. The program output is also shown below. defis_palindrome(s):iflen(s)<1:returnTrueelse:ifs[0]==s[-1]:returnis_palindrome(s[1:-1])else:returnFalsea=str(input("Enter string:...
Check Palindrome in Python Using List Slicing Example # Enter stringword=input()# Check for palindrome strings using list slicingifstr(word)==str(word)[::-1]:print("Palindrome")else:print("Not Palindrome") The program begins by prompting the user to input a string using theinput()function...
Determine whether an integer is a palindrome. Do this without extra space. 这一题描述很简单,判断一个数字是否是回文数,不要用额外的空间。其实我觉得逻辑不是那么简答,2个点需要注意,怎样的数字是回文数和怎样算不使用额外空间? 1、先考虑什么数字是回文数?
def Palindrome_number(): num=input('请输入数字:') if not num.isdigit(): raise Exception('输入错误哦!请输入数字!') if num==num[::-1]: print(f'{num}是回文数') else: print(f'{num}不是回文数') try: print(Palindrome_number()) ...
[LeetCode]题解(python):009-Palindrome Number 题目来源: https://leetcode.com/problems/palindrome-number/ 题意分析: 这题是要判断一个int是否一个回文数,要求不能申请额外的空间。 题目思路: 这题也是一个简单的题目,由于不能申请额外的空间,所以不能将int转换成string来处理。根据回文数的定义,我们可以...
所谓回文数 Palindrome Number,即从左边开始读或从右边开始读,两者结果一致。判断的目标数字为整数,包括负数。 比如12321,123321,或者 3,都是回文数。 -12321不是回文数;-1也不是回文数。 解法1. 简单解法:将整数转换为字符串 转换之后,Python有转换的 reverse 函数,将字符串进行反转:str[::-1]。
(1, n): # Check if 'x' is a factor of 'n' (divides 'n' without remainder) if n % x == 0: # If 'x' is a factor of 'n', add it to the 'sum' sum += x # Check if the 'sum' of factors is equal to the original number 'n' return sum == n # Print the result ...