# Python program to check prime number # Function to check prime number def isPrime(n): return all([(n % j) for j in range(2, int(n/2)+1)]) and n>1 # Main code num = 59 if isPrime(num): print(num, "is a prime number") else: print(num, "is not a prime number") ...
Python program to check prime number using object oriented approach# Define a class for Checking prime number class Check : # Constructor def __init__(self,number) : self.num = number # define a method for checking number is prime or not def isPrime(self) : for i in range(2, int(...
Program to calculate LCM of two numbers in Python def cal_lcm(a,b): if a > b: greater = a else: greater = b while(True): if((greater % a == 0) and (greater % b == 0)): lcm = greater break greater += 1 return lcm num1 = 54 num2 = 24 print("The L.C.M. ...
To find the square of a number - simple multiple the number two times. 要查找数字的平方-将数字简单乘以两次。 Program: 程序: # Python program to calculate square of a number # Method 1 (using number*number) # input a number number = int (raw_input ("Enter an integer number: ")) # ...
But to calculate the middle element you will require the length of the entire LinkedList, right? So this is where the Two-Pointer Technique also known as the Slow and Fast Pointer method. You will have 2 pointers one moving twice as fast as the other. In other words, the fast pointer ...
SILENT_MODE = False # If set to True, program doesn't print anything. NONLETTERS_PATTERN = re.compile('[^A-Z]') def main(): # Instead of typing this ciphertext out, you can copy & paste it # from https://www.nostarch.com/crackingcodes/: ciphertext = """Adiz Avtzqeci Tmz...
Write a Python program to calculate the difference between the squared sum of the first n natural numbers and the sum of squared first n natural numbers.(default value of number=2). Test Data: If sum_difference(12) Expected Output : ...
Calculate n = p * q: print('Generating p prime...') while p == q: p = primeNum.generateLargePrime(keySize) q = primeNum.generateLargePrime(keySize) n = p * q # Step 2: Create a number e that is relatively prime to (p-1)*(q-1): print('Generating e that is relatively ...
When you combine the individual pieces of the puzzle—that is, the aperture, the shutter speed, and the ISO speed—you’ll be able to calculate a single exposure value (EV), which describes the average amount of captured light. You can then use it to derive a log mean of the luminance...
import math # 计算三角函数值 def calculate_trigonometric(angle_degrees): angle_radians = math.radians(angle_degrees) # 将角度转换为弧度 print(f"{angle_degrees} 度等于{angle_radians}弧度") angle_radians = math.radians(angle_degrees) sin_value = math.sin(angle_radians) cos_value = math.cos...