Python program to check leap year by using the calendar module # importing the moduleimportcalendar# input the yearyear=int(input('Enter the value of year: '))leap_year=calendar.isleap(year)# checking leap yearifleap_year:# to check conditionprint('The given year is a leap year.')else:...
calendar.isleap(year) returns a boolean if the year is a leap year. One thing you need to know is that the function depends on the calendar module, So you must import the calendar module at the start of your Python script or program Also Read: Basic Python Programs 3) Divisibility Meth...
6.程序实现的功能:输人某年某月某日,判断这一天是这一年的第几天,Python代码如下: d e f leap(year):$$ l e a p = 0 $$$ i f ( y e a r \% 4 0 0 = = 0 ) o r ( ( y e a r \% 4 = = 0 ) a n d ( y e a r \% 1 0 0 ! = 0 ) ) : $$$ l e a ...
1、定义一个is_leap(year)函数,该函数可以判度year是否为闰年。若是闰年,则返回True;否则返回False。 import sys def is_leap(year): year = int(year) if year % 4 != 0: return False elif year % 100 != 0: return True elif year % 400 != 0: return False else: return True while(True)...
Python Program to Check Leap Year How to Calculate Leap Year The year includes 365 days, but the leap year includes 366 days. This extra day in the leap year is included in February. Logically, the year perfectly divisible by four is known as Leap year except for the century decades. ...
Python Leap Year #The test case is passing 4/6. I don't know what is wrong with my code, please help year = int(input()) if year % 4 == 0: if year % 100 == 0: if year % 400 == 0: print("Leap year") else: print("Not a leap year") else: print("Not a leap year...
Python程序LeapYear源码 import math def valid(month,day,year):if day>31:return False elif month==2:if leap(year):if day <=29:return True else:return False else:if day<=28:return True else:return False elif month==4 or 6 or 9 or 11:if day>31:return False else:return True else:r...
This one has got the better of me. year = int(input()) if year % 4 == 0: if year % 100 == 0: if year % 400 == 0: print ("Leap year") else: print ("Not a leap year") Appreciate any help as to why that does not work rather than the answer to help better my underst...
Thecalendar.isLeap()method takes an integer year value and returnstrueorfalseif the argument is a leap year or not. Therefore, we can apply decision statements to display our personalized messages. Let’s test this code by running the program for different years: ...
Given a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise, returnFalse. Note that the code stub provided reads from STDIN and passes arguments to theis_leapfunction. It is only necessary to complete theis_leapfunction. ...